1) cscΘ = - 2
=>
1
------ = - 2
sinΘ
=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant
=> Θ = 180° + 30° = 210°
and Θ = 360° + 30° = 330°
2) tan Θ = √3
=> Θ = 60° and Θ = 180° + 60° = 240°
The distance between two points knowing theirs coordinates:
AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(-2,4) & B(0,-6) Given
A(x₁,y₁) & B(y₂,y₁)
AB =√[(0-(-2))²+(-6-4)²] =√(104) = 10.198 ≈ 10.2
Answer:
1.80 this is the correct answer
Answer:
A=13684.7776
Step-by-step explanation:

