Answer:
A, B, D
Step-by-step explanation:
2 x 3x =6x - 2 times 9y which equals 18y+ and 2 times 18 equals 36 so 2(3x-9y+18)
Well we have a function and its body is a fraction so we need to handle those edge cases, namely division by 0.
That means solving the following equation,
.
As we can see x must not be equal to 0 or 2 if we do not want to end up with division by zero situation.
The domain is therefore
.
Writing this as interval would be,
.
Hope this helps.
Simplest Form: 9/4
Decimal Form: 2.25
Mixed Number Form: 2 1/4
Hope this helps! :)
<h3>
Answer:</h3>
99.90%
<h3>
Step-by-step explanation:</h3>
STEPS:
- Find the total amount
- Find out what number of what we want to know the percentage of there are out of the whole amount there is. (Divide the percentage amount we want to find by the total amount)
- Turn into a percentage by multiplying by 100
Find the total sum
30.2 mil = 30,200,000 small businesses + 30,000 other = 30,230,000 total
Find the fraction that small businesses make up of the total

Convert to percentage
0.9990 → % = 0.9990 × 100 = 99.90%
Hope this helps,
The answer:
the main formula of the circle's equation is
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius
if a point A(x', y') passes through the circle, so the equation of the circle can be written as
(x'-a)²+ (y'-b)² = R², and that is a main formula.
<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²
and we know that R= OA = OC= OB,
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies
x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)² so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
-5= -2x -4y, when x = -3 /2 we obtain y = 2
the center is C(-3/2, 2)