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Lady_Fox [76]
3 years ago
11

I NEED MEGA HELP WITH THIS QUESTION

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0

Answer:

C. y =  -  \frac{1}{4} x - 2

Step-by-step explanation:

To find slope using coordinates, use the formula above.

(4, - 3) \: (0, - 2)→ \frac{ - 2 - ( - 3)}{0 - 4}→ \frac{ - 2 + 3}{ - 4} → -  \frac{1}{4}

Now, using the y = mx + b formula, plug in -  \frac{1}{4} as m (slope) and either coordinate as the x and y values. It looks like this:

- 3 =   - \frac{1}{4}(4)  + b

To solve for b, continue to use PEMDAS.

- 3 =   - \frac{1}{4}(4)  + b→ - 3 =  - 1 + b→ - 2 = b

Now use m and b to solve for your equation:

y =  -  \frac{1}{4} x - 2

The answer is C.

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Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not
Verizon [17]

Answer: \left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-2}{4-1}

   = -\frac{5}{3}

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = -\frac{5}{3}(x - 1)

y - 2 = -\frac{5}{3}x + \frac{5}{3}

y      = -\frac{5}{3}x + \frac{11}{3}

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ -\frac{5}{3}x + \frac{11}{3}

8 ___ -\frac{5}{3}(-2) + \frac{11}{3}

8 ___ \frac{1}{3}

8 > \frac{1}{3}

so ≤ makes the statement False

⇒ y ≤ -\frac{5}{3}x + \frac{11}{3}

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.  

y < 8   or  x > -2 are two examples.


---> I just realized that the system can be simpler than what I did above:

\left \{ {{x>-2} \atop {y < 8}} \right



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Simplifying, we have,

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Substituting the values of a, b and c in the equation ax+by=c, we have,

1x+0y=3

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