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Olegator [25]
3 years ago
11

X^2+(3x-9)^2=(2x+1)^2

Mathematics
1 answer:
Delvig [45]3 years ago
6 0
                     x² + (3x - 9)² = (2x + 1)²
           x² + (3x - 9)(3x - 9) = (2x + 1)(2x + 1)
x² + (9x² - 27x - 27x + 81) = (4x² + 2x + 2x + 1)
         x² + (9x² - 54x + 81) = 4x² + 4x + 1
         (x² + 9x²) - 54x + 81 = 4x² + 4x + 1
                10x² - 54x + 81 = 4x² + 4x + 1
                <u>- 4x²                   - 4x²              </u>
                  6x² - 54x + 81 = 4x + 1
                 <u>      + 54x        + 54x      </u>
                           6x² + 81 = 58x + 1
                          <u>       -    1            - 1</u>
                           6x² + 80 = 58x
                  6x² - 58x + 80 = 0
                                       x = <u>-(-58) +/-√((-58)² - 4(6)(80)</u>
                                                              2(6)
                                       x = <u>58 +/- √(3364 - 1920)</u>
                                                            12
                                       x = <u>58 +/- √(1444)</u>
                                                      12
                                       x = <u>58 +/- 38</u>
                                                   12
                                       x = <u>58 + 38</u>        x = <u>58 - 38</u>
                                                 12                      12
                                       x = <u>96</u>                x = <u>20</u>
                                             12                      12
                                       x = 6                  x ≈ 1.67
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Help please i don’t know the answer
son4ous [18]

Answer:

6A=8B=6\left[\begin{array}{ccc}-4&-1&-9\\-9&6&9\\-1&-1&3\end{array}\right] -8\left[\begin{array}{ccc}-10&-2&-5\\9&-7&-1\\9&-4&2\end{array}\right]

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So,~ A ~is ~your~ answer~

<u>---------------------------</u>

<u>hope it helps..</u>

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7 0
3 years ago
What is the equation for this line
pogonyaev

The equation of the line is y=\frac{-1}{5} x-\frac{21}{5}.

Solution:

The points on the line are (–6, –3) and (4, –5).

 x_{1}=-6, y_{1}=-3, x_{2}=4, y_{2}=-5

Slope of the line:

 $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

 $m=\frac{-5-(-3)}{4-(-6)}

 $m=\frac{-5+3}{4+6}

$m=\frac{-2}{10}

$m=\frac{-1}{5}

Point-slope formula:

 y-y_{1}=m\left(x-x_{1}\right)

 $y-(-3)=\frac{-1}{5}(x-(-6))

 $y+3=\frac{-1}{5}(x+6)

 $y+3=\frac{-1}{5} x-\frac{6}{5}

Subtract 3 from both sides of the equation.

$y=\frac{-1}{5} x-\frac{21}{5}

The equation of the line is  y=\frac{-1}{5} x-\frac{21}{5}.

6 0
3 years ago
A new Neighborhood Activity Complex is being built in Safe Harbor. The perimeter of the rectangular playing field is 486 yards.
siniylev [52]

Answer:

the two lengths= 194 each side

teh two widths= 49 on each side

194+194+49+49= 486

Step-by-step explanation:

486= 2l+2w

l=4w-2

486-2w=2l -divide that by 2

243-w=l

243-w=4w-2

245=5w -divide that by 5

49=w

l=4(49)-2

l=194

w=49

6 0
4 years ago
cinema A sells a twelve pack of moive passes for $66. Cinema B selles a five pack of moive passes for $28. Find the cost per moi
nekit [7.7K]
CINEMA A sells each movie pass for $5.50, and CINEMA B sells each movie pass for $5.60.

To find the cost of each pass in Cinema A, all you would have to do it divide 66 by 12, where you would get 5.5, which in other words would be $5.50. And to find the cost of each pass in Cinema B, you wound divide 28 by 5,and you would get 5.6, which is in other words, $5.60.
5 0
4 years ago
Help meh emergency. No links please give a right answer, need helppppp
andre [41]

Answer:

70.91 x 10 = 709.1

70.91 x 100 = 7,091

70.91 x 1000 = 70,910

8 0
3 years ago
Read 2 more answers
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