Question

The maintenance department at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 35 and a standard deviation of 6. Using the 68-95-99.7% rule, what is the approximate percentage of light bulb replacement requests numbering between 35 and 41?

Answer 1

Answer: 34%

Step-by-step explanation:

Given : The distribution of the number of daily requests is bell-shaped and has a $\mu=35$ and $\sigma=6$.

We can see that 41 = 35+6 , it 41 is one standard deviation from mean in the right side . (1)

According to the 68-95-99.7% rule, 68% of the population falls within 1 standard deviation from the mean.

34% (half of 68%) of the population on right side and 34% population on the left side of the density curve.              (2)

From (1) and (2), the approximate percentage of light bulb replacement requests numbering between 35 and 41= 34%