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kodGreya [7K]
3 years ago
15

A man age is three times his sons age. ten years ago was five times his sons age. find their current age.

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

The son is 20

The man is 60

Step-by-step explanation:

We can set up this equation with what we know. Let <em>m</em> stand for the Man's current age, and let <em>s</em> stand for his son's current age.

We know the Man's current age is three times that of his son, so this equation can be written as: <em>m = 3s</em>

Ten years ago means the man's current age <em>minus</em> 10 years. So it is <em>m-10</em>. So ten years ago he was 5 times his son's age 10 years ago, <em>5(s-10)</em>

This can be written as: <em>m-10=5(s-10)</em>

Solve with either substitution or elimination, the choice is yours, it doesn't really matter which method you use. I'll be using substitution.

<em>m-10=5(s-10)</em>

<em>3s-10= 5s-50</em>

<em>40=2s</em>

<em>20 = s</em>

The son is <em>20</em> years old.

We know the man is currently 3 times his son's age, because <em>m=3s</em>, so just solve for m since you now know the value of <em>s.</em>

<em>m=3s</em>

<em>m=3(20)</em>

<em>m=60</em>

The man is <em>60</em> years old

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