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kodGreya [7K]
3 years ago
15

A man age is three times his sons age. ten years ago was five times his sons age. find their current age.

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

The son is 20

The man is 60

Step-by-step explanation:

We can set up this equation with what we know. Let <em>m</em> stand for the Man's current age, and let <em>s</em> stand for his son's current age.

We know the Man's current age is three times that of his son, so this equation can be written as: <em>m = 3s</em>

Ten years ago means the man's current age <em>minus</em> 10 years. So it is <em>m-10</em>. So ten years ago he was 5 times his son's age 10 years ago, <em>5(s-10)</em>

This can be written as: <em>m-10=5(s-10)</em>

Solve with either substitution or elimination, the choice is yours, it doesn't really matter which method you use. I'll be using substitution.

<em>m-10=5(s-10)</em>

<em>3s-10= 5s-50</em>

<em>40=2s</em>

<em>20 = s</em>

The son is <em>20</em> years old.

We know the man is currently 3 times his son's age, because <em>m=3s</em>, so just solve for m since you now know the value of <em>s.</em>

<em>m=3s</em>

<em>m=3(20)</em>

<em>m=60</em>

The man is <em>60</em> years old

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Step-by-step explanation:

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Firstly,
thanks for posting this.

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No panic
√ 81.x^8 x <span>√ y^5
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insens350 [35]
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Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
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Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

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So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

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