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Anna11 [10]
3 years ago
11

I’ll give u brainliest please help asap

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

c, 14

Step-by-step explanation:

pishuonlain [190]3 years ago
5 0

Answer:

the ansewr is b

Step-by-step explanation:

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Que is on pic.i can't able to type in text.
ad-work [718]
It's not difficult to compute the values of A and B directly:

A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}
A=\tan^{-1}(\sin\theta)-\dfrac\pi4

B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt
B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}
B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2

Let's assume 0, so that |\csc\theta|=\csc\theta.

Now,

\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}
\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}
\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)
\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in A and B.
3 0
3 years ago
The short side of a triangle is always opposite the
Goryan [66]
That would be B
- smallest  angle
7 0
3 years ago
If anyone can help me out I would truly appreciate it <br> Please show me step by step
wel

Answer:

5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

0.3y + y/z

<em>y</em> = 10

<em>z</em> = 5

<u>Step 2: Evaluate</u>

  1. Substitute in variables:                                                                                     0.3(10) + 10/5
  2. Multiply:                                                                                                             3 + 10/5
  3. Divide:                                                                                                               3 + 2
  4. Add:                                                                                                                   5
3 0
2 years ago
An astronaut weighs 170 pounds on Earth and 400 pounds on Jupiter. The astronaut captures an alien that weighs 120 pounds on Jup
Svet_ta [14]
B. 51 pounds.
<span>You multiply your weight on Earth (170) and the Alien's weight one Jupiter (120) and divide it by your weight on Jupiter (400).</span>


5 0
3 years ago
Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).
egoroff_w [7]
Slope intercepf is y=mx+b wherem=slope and b= y intercept
slope is found by doing
(y1-y2)/(x1-x2)
points are (6,-1) and (-3,2)
(x,y)
x1=6
y1=-1
x2=-3
y2=2
subsitute
(-1-2)/(6-(-2))=-3/(6+2)=-3/8
slope=-3/8
subsitute
y=-3/8x+b
subsitute and solve for b
(-3,2)
x=-3
y=2
2=-3/8(-3)+b
2=9/8+b
2=16/8
subtract 9/8 from both sides
16/8-9/8=b
7/8=b
y=-3/9x+7/8 is the equation
5 0
3 years ago
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