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Step-by-step explanation:
Look at the photo below for the answer.
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My property ..............................
The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
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Answer: C
Step-by-step explanation:
3(x+4y-2)
3x+12y-6
Answer:
Below in bold.
Step-by-step explanation:
c) 3 x (9^2)^3/4 x ((81^3)^5/6
= 3 x 81^3/4 x 81^15/6
= 3 x 81^(3/4 + 15/6)
= 3 x 81^13/4
= 3 x 3^13
= 3^14
= 4,782,969.
f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2
= 5^-2 x^2y^-4 / 625 x^4y^-2
= 5^-2 x^-2 y^-2 / 5^4
= 5^-6 x^-2y^-2
= 0.000064x^-2y^-2.