Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
58,800.
3600 divided by 9000 is 0.4
147,000 * 0.4 is 58,800
Answer:
A. I can't quite see the question, but I'm pretty sure it's A
Step-by-step explanation:
Sin(A) = 1/3
Sin^2(A) + Cos^2(A) = 1
(1/3)^2 + cos^2(A) = 1
1/9 + cos^2(A) = 1
cos^2(A) = 1 - 1/9
cos^2(A) = 8/9
cos(A) = √(8/9)
√8 = √(2 * 2 * 2) = 2√2
√9 = 3
cos(A) = 2√2/3
Answer:
4g-2/5
Step-by-step explanation:
If X = 23, the. 23 - 6 = 17.
