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kotegsom [21]
3 years ago
8

How can you make 24 out of 5,3,3,2

Mathematics
2 answers:
Temka [501]3 years ago
5 0

Answer:

You can make 24 by using +,-,*,/, () with the given numbers

Step-by-step explanation:

Elodia [21]3 years ago
3 0
24/5=6
24/3=8
24/2=12
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X + 4 is prime x2 – 9 can be factored using the formula.
Anna71 [15]

We are given two binomials: x+4 , x^2-9.

x+4 can't be factored. Therefore,  it is a prime.

Let us work on x^2-9.

9 could be written as 3^2.

Therefore, x^2-9 = x^2 - 3^2.

Now, we can apply difference of the squares formula to factor it.

We know a^2 -b^2 = (a-b) (a+b).

Therefore,  x^2 - 3^2 can be factored as (x-3) (x+3).

So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).

3 0
3 years ago
Read 2 more answers
Jason wants to create a box with the same volume as the one shown below. He wants the length to be 4 inches. What would be the m
jeyben [28]

Answer:

Width-6

height-3

I determinded the width and the height by counting how many cubic blocks there are up and down.

Step-by-step explanation:

8 0
3 years ago
Write the value of 4 in 305,444
BigorU [14]
Divide 305444 by 4

305444 / 4
76361

so
76361 times 4 is equal to 76361
3 0
3 years ago
Read 2 more answers
What is the solution to x^6 – 6x ^5 + 15x ^4 – 20x ^3 + 15x^ 2 – 6x + 1 ≥ 0? x = 0 x = 1 all real numbers all real numbers excep
g100num [7]

Answer:

Answer: C all real numbers

8 0
3 years ago
riding find the length of the hypotenuse of the right triangle use pencil and paper explain how you can interpret the Pythagorea
noname [10]

Solution

Question 1:

- Use of the area of squares to explain the Pythagoras theorem is given below

- The 3 squares given above have dimensions: a, b, and c.

- The areas of the squares are given by:

\begin{gathered} \text{For square of length }a\to a^2 \\ \text{For square of length }b\to b^2 \\ \text{For square of length }c\to c^2 \end{gathered}

- The Pythagoras theorem states that:

"The sum of the areas of the smaller squares add up to the area of the biggest square"

Thus, we have:

c^2=a^2+b^2

Question 2:

- We can apply the theorem as follows:

\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\  \\ c=\sqrt[]{676} \\ c=26 \end{gathered}

Thus, the value of c is 26

7 0
1 year ago
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