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Oduvanchick [21]
3 years ago
14

Quincy is trying to estimate the height of a tree in his backyard. he measures the tree’s shadow as 12 ft. he stands near the tr

ee and measures his own shadow as 3 ft. quincy knows that he is about 5 ft tall. he estimates the height of the tree by following these steps:
Mathematics
1 answer:
slava [35]3 years ago
3 0
I believe he should add 2ft to the height of the tree as well
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a box has a length of 12 inches and a width of 10 inches . If the volume of the box is 960 cubic inches. What is it's height?​
Marizza181 [45]

length* width

12*10= 120

Volume /120

960/120=8

height is 8 inches

5 0
3 years ago
Which expression is NOT a polynomial?
butalik [34]

Answer:

The last expression.

Step-by-step explanation:

The last expression is not a polynomial because x is in the denominator of the second term.

5 0
3 years ago
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Write the number in standard notation.<br><br> 9 x 10^4
bonufazy [111]
10^4 = 10,000

9 x  10,000 = 90,000
7 0
3 years ago
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A stack of cards is numbered 1 through 50 if a student selects a card what is the probability that the student will select a car
maw [93]

Answer:

The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08

Step-by-step explanation:

To solve this exercise we have to know that the probability is calculated by dividing the number of favorable events by the number of possible events.

f = favorable events

we will count how many numbers between 1 and 50 have the same number in the ones place in the tens place

11 ; 22 ; 33 ; 44

as we can see there are 4 numbers

f = 4

p = possible events

the number of possible events is given by the number of cards in the deck

p = 50

4/50 = 0.08

The probability that the student will select a card that has both the same number in the ones place in the tens place is 0.08

7 0
3 years ago
Use double integrals to calculate the area inside the ellipse whose semiaxes have length a and b
Stells [14]
The general equation of an ellipse centered at the origin with its semiaxes coinciding with the coordinate axes is given by

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

Substituting x=a\cos\theta and y=b\sin\theta into the above equation gives the Pythagorean identity, so we can use polar coordinates quite nicely to our advantage.

If \mathcal E is the ellipse with the equation above, the area is given by the double integral

\displaystyle\iint_{\mathcal E}\mathrm dA=\iint_{(x/a)^2+(y/b)^2\le1}\mathrm dx\,\mathrm dy

Let x(r,\theta)=ar\cos\theta and y(r,\theta)=br\sin\theta, so that the Jacobian matrix is

\mathbf J=\begin{bmatrix}x_r&x_\theta\\y_r&y_\theta\end{bmatrix}=\begin{bmatrix}a\cos t&-ar\sin t\\b\sin t&br\cos t\end{bmatrix}

and the magnitude of its determinant is |\det\mathbf J|=|abr|=abr

since in polar coordinates we use the convention that r\ge0, and a,b>0 because they are lengths.

Now, the area is given by

\displaystyle\iint_{\mathcal E}\mathrm dA=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}abr\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi a b\int_{r=0}^{r=1}r\,\mathrm dr
=\pi a b
4 0
4 years ago
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