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Andru [333]
3 years ago
13

Please help urgently.

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

No

Step-by-step explanation:

He's only won 50% of the games bc he lost one and one one. 1/2

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Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +
Veronika [31]

Answer:

Verified

y(x) = \frac{3Ln(x) + 3}{x}

y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

                           x^2y' +xy = 3

- A general solution to the above ODE is also given as:

                          y = \frac{3Ln(x) + C  }{x}

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

                          y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x)  }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

                          -\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3

- Therefore, the complete solution to the given ODE can be expressed as:

                        y ( x ) = \frac{3Ln(x) + 3 }{x}

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

                         y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)

- Therefore, the complete solution to the given ODE can be expressed as:

                        y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}

                           

Download docx
6 0
3 years ago
Help me pls solve this
Serjik [45]

Answer:

1/8  (Decimal: 0.125)

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Yuki works at a garden store. She is stacking 40-pound bags of soil. Use the equation w=40b to find the total weight, w, of 5 ba
NeTakaya

Answer:

w= 40b

w=40× 5

w=200

......

4 0
3 years ago
a cube has sides of lengths a -3 which of the following expression best represents the volume of the cube
Semenov [28]

Answer: -27


Step-by-step explanation: the cube has a volume of -27 because -3 to the 3rd power (cubed) is -27

Hope this helps ☺


7 0
3 years ago
What is the product of (–0.9)(–2.4)?<br> –3.3<br> –2.16<br> 2.16<br> 3.3
saul85 [17]
The answer would be 2.16.

This is because the two negatives would cancel each other out when multiplying. This would basically make the question 0.9*2.4.
Now 3.3 is definitely not less than 2.4, so the answer would be 2.16
7 0
3 years ago
Read 2 more answers
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