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Zina [86]
3 years ago
14

Hows new to this I know I am

Mathematics
2 answers:
Ludmilka [50]3 years ago
6 0

just work hard and help others as much as they help you:)

Airida [17]3 years ago
6 0
Just help by answering others questions to their hw if you know it
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Help me please...<br> At least an explanation
In-s [12.5K]

Answer:

do u still need this question answeered?

Step-by-step explanation:

4 0
2 years ago
If x = 3 + 2√2, then the value of (x - 1/x) is<br><br> a) 4√2<br> b) 2√4<br> c) 8
vitfil [10]
Your answer is: A. 4/2

Hope this helps and happy holidays!!
5 0
3 years ago
I need help. please answer.
lana66690 [7]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
Is 6-6 and 1-6 equal
uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

7 0
3 years ago
The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in
Elanso [62]

Answer:

0 < t < \frac{5}{3}

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0
3 years ago
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