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jeka94
3 years ago
14

Please help me with this literal equation!

Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Answer:

x = \frac{n-20}{3a}

Step-by-step explanation:

Given

\frac{3ax-n}{5} = - 4

Multiply both sides by 5

3ax - n = - 20 ( add n to both sides )

3ax = - 20 + n = n - 20

Isolate x by dividing both sides by 3a

x = \frac{n-20}{3a}

VikaD [51]3 years ago
4 0

Answer:

x=(-20+n) / 3a

Step-by-step explanation:

(3ax-n) /5 = -4

⇒3ax-n = -20         [multiplied by 5 on both sides]

⇒3ax=-20+n           [add "n" on both sides]  

⇒x=(-20+n) / 3a      [divide both sides by "3a"]

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