Answer:
<em>x² - 28x√x + 294x - 1372√x + 2404 </em>
Step-by-step explanation:
f(x) =
+ 3
g(x) = x - 7
h(x) = √x
f(g(h(x))) - ?
g(h(x)) = √x - 7
f(g(h(x))) =
+ 3 = ( √x - 7 )² × ( √x - 7 )² + 3 =
= (x - 14√x + 49)(x - 14√x + 49) + 3 =
= x² - 14x√x + 49x - 14x√x + 196x - 686√x + 49x - 686√x + 2401 + 3 =
= <em>x² - 28x√x + 294x - 1372√x + 2404</em>
Your answer is: 63 is 90% of 70.
The work (if needed) is shown above :)
31 students do their homework every night
-2,-3
-3, -4
-4, -5
you are showing the line of growth in the graph.
Answer:
- Solution of equation ( x ) = <u>7</u>
Step-by-step explanation:
In this question we have given with an equation that is <u>4</u><u> </u><u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u><u>)</u><u>.</u> And we are asked to solve this equation that means we have to find the value of <u>x</u><u>.</u><u> </u>
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
<u>
</u>
<u>Step </u><u>1</u><u> </u><u>:</u> Removing parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 8 from both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Subtracting 18 from both sides :

On further calculations we get :

<u>Step </u><u>4</u><u> </u><u>:</u> Dividing with 2 on both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>or </u><u>we </u><u>can </u><u>say </u><u>that </u><u>value </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
We are verifying our answer by substituting value of x in given equation. So ,
- 4 ( 5x - 2 ) = 2 ( 9x + 3 )
- 4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]
- 4 ( 35 - 2 ) = 2 ( 63 + 3 )
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>value</u><u> for</u><u> x</u><u> is</u><u> </u><u>correct </u><u>.</u>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>