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Lynna [10]
2 years ago
8

Jackson weighed 250 pounds on January 1rst. He weighed himself six months later and saw he weighed 217 pounds. At what rate is J

ackson losing weight per month
Mathematics
1 answer:
Morgarella [4.7K]2 years ago
8 0

Here we find how many pounds he lost (which is 33) then divide that by 6 (because he weighed himself 6 months later) which then we get the fact that jack lost 5.5 pounds a month.

Hope i could help you out here! :)

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If the length of a rectangle is 2x + 4 and the width is x - 2. write
Bess [88]

Answer:

  P = 6x +4

Step-by-step explanation:

Use the given values in the formula for the perimeter of a rectangle:

  P = 2(L +W)

__

You have ...

  L = 2x +4

  W = x -2

So, the perimeter is ...

  P = 2((2x +4) +(x -2)) = 2(3x +2)

  P = 6x +4

The perimeter of the rectangle is 6x+4.

3 0
2 years ago
3. What information does a compound's empirical formula give us?
Anna11 [10]

Answer:

A

Step-by-step explanation:

empirical formulas are the simplest form of notation so they provide the lowest whole number ratio between the elements in a compound

4 0
3 years ago
Alex lady sketch for a homemade soccer goal he plans to build . Do you go will be in the shape of a triangular prism . The legs
Otrada [13]
The triangular prism has a volume of
.. V = Bh = (1/2)*(4ft *8 ft)*(24 ft) = 384 ft^3
7 0
3 years ago
Please help. i not smart
____ [38]

Answer:

It is hard to see the numbers.

But I am pretty sure it is 6x+6.

Step-by-step explanation:

Hope this helps! :D

4 0
2 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
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