Question

Which equation represents a line that passes through (4,1/3)and has a slope of 3/4

Answer 1

Answer:

y = $\frac{3}{4}$ x + $\frac{-8}{3}$ or 12y = 9x -32 or y - 1/3 =3/4(x-4)

Step-by-step explanation:

The equation of a line in the slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

The other form is the point-slope form where the point (x₁, y₁)  and a slope m are given, and you  have to plug it into formula:

y – y₁ = m(x – x₁)

Here:

y - 1/3 =3/4(x-4)multiply both sides by 12 to loose fraction

12y -4 = 9(x-4) distribute

12y -4  = 9x -36 add 4 on both sides

12y = 9x -32 divide by 12

y = $\frac{9}{12}$ x + $\frac{-32}{12}$ simplify factions

y = $\frac{3}{4}$ x + $\frac{-8}{3}$