All categories

2 years ago

Which of the following expressions cannot be factored?

Mathematics

1 answer:

devlian [24]2 years ago

3 0

Answer:

C. 3x + 8

Step-by-step explanation:

A. can be factored; Factor 5 from all terms:

(15x - 10)/5 = 3x - 2

B. can be factored; Factor 4 from all terms:

(4x + 8)/4 = x + 2

D. can be factored; Factor 2 from all terms:

(2x - 2)/2 = x - 1

You might be interested in

Can someone help me in this please

Karolina [17]

Is the value of b is 5?

5 0

3 years ago

Really need help on this timed

SSSSS [86.1K]

Answer:

10 units

Step-by-step explanation:

The distance from the point (0,0) to (10,0) is 10 units

4 0

3 years ago

Read 2 more answers

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

The volume of a large aquarium is 210 yd. It is 3 yd wide and 2

Pavel [41]

Length of the aquarium is 35 yd

Step-by-step explanation:

Step 1: Volume of the aquarium = 210 yd³ given by Volume = length × width × height. Width = 3 yd and Height = 2 yd

Length = Volume/Width × Height

= 210/3 × 2 = 210/6

= 35 yd

5 0

2 years ago

In which quadrant do the points (-1,-2) and (-2,3) lie?

vitfil [10]

Answer: 3 for the first one. and 2 for the second

5 0

2 years ago