Answer:
Answer for the question:
The Rockwell hardness of a metal is determined by impressing a hardened point into the surface of the metal and then measuring the depth of penetration of the point. Suppose the Rockwell hardness of a particular alloy is normally distributed with mean 69 and standard deviation 2.7.
a. If a specimen is acceptable only if its hardness is between 67 and 75, what is the probability that a randomly chosen specimen has an acceptable hardness?
b. If the acceptable range of hardness is (69-C, 69+C), for what value of C would 95% of all specimens have acceptable hardness?
c. If the acceptable range is as in part (a) and the hardness of each of ten randomly selected specimens is independently determined, what is the expected number of acceptable specimens among the ten?
d. What is the probability that at most eight of ten independently selected specimens have a hardness of less than 72.84(HINT Y=number among the ten specimens with hardness less than72.84 is a binomial variable; what is p?)
is given in the attachment.
Step-by-step explanation:
Answer:
Answer is right!
Step-by-step explanation:
Have a nice day!
☁️ Answer ☁️
annyeonghaseyo!
I Got:
√5/2
Here's the Decimal Form:
1.11803398
Hope it helps.
Have a nice day noona/hyung!~ ￣▽￣❤️
Answer:
This is an percentage change question, by any chance you have a maths textbook, look for units that contains the topic: Percentage Change. Now, let's get solving! :)
Step-by-step explanation:
Firstly, you must multiply 4.5% with 56. That is: shipping fees x purchase price
That gives ($) 2.52 (this is your answer)
No addition/totaling needed as the question asked ONLY for the shipping fees.
Stay safe and Merry Christmas! :)
<h3>
Answer: 21.4 square meters</h3>
Work Shown:
A = area of the front triangular face
A = base*height/2
A = 2*1.7/2
A = 1.7
L = lateral area
L = (perimeter of the base)*(depth)
L = (2+2+2)*(3)
L = 18
SA = total surface area of a triangular prism
SA = 2*A+L
SA = 2*1.7+18
SA = 21.4 square meters
