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Semmy [17]
4 years ago
5

Nth term of sequence 40 35 30 25 20

Mathematics
2 answers:
Deffense [45]4 years ago
7 0
The answer is 15 (Fifteen)
Mamont248 [21]4 years ago
7 0
If your going backwards the awnser would be 0 if you're going forward the awnser would be 60 I hope I helped you
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C=Wtc/1,000 Solve for w
Mice21 [21]
I can not answer that for u
7 0
3 years ago
Given two sets of polar coordinates that could be used to play the given point
topjm [15]

Answer:  a.  (2.5, 300°)  and  (-2.5, 120°)

               b.  (4, 270°)    and   (-4, 90°)

<u>Step-by-step explanation:</u>

Polar coordinates are written as (r, θ)    where

  • r is the radius
  • θ is the angle

In the first graph, the radius is 2.5 and the angle is 300° --> (2.5, 300°)

You can also list the radius as -2.5 at angle 120° --> (-2.5, 120°)

                                                                           ↓

                                                                    (300 - 180)

In the second graph, the radius is 4 and the angle is 270° --> (4, 270°)

You can also list the radius as -4 at angle 90° --> (-4, 90°)

                                                                      ↓

                                                                (270 - 180)

5 0
3 years ago
1. Describe how transformations can affect a parent function and then describe the transformation of f(x) = -2/x - 7 - 3 from f(
ss7ja [257]

я не знаю что тут написано поэтаму я русский ::3

5 0
3 years ago
82.50 +46.63 i need help
RSB [31]
129.13, I believe.

Hope this helps.
6 0
3 years ago
Read 2 more answers
Rationalise the equation :<br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%20%5E%7B2%7D%20%7D%7B%20%5Csqrt%7Bx%5E%7B2%7D
Nat2105 [25]

Answer:

\sqrt{x^2+y^2}-x

Step-by-step explanation:

\textsf{Mulitply by}\quad\dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}:

\implies \dfrac{y^2}{\sqrt{x^2+y^2}+x} \times \dfrac{\sqrt{x^2+y^2}-x}{\sqrt{x^2+y^2}-x}

\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2}+x)(\sqrt{x^2+y^2}-x)}

\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{(\sqrt{x^2+y^2})^2-x^2}

\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{x^2+y^2-x^2}

\implies \dfrac{y^2(\sqrt{x^2+y^2}-x)}{y^2}

\textsf{Cancel the common factor}\:y^2:

\implies \sqrt{x^2+y^2}-x

6 0
3 years ago
Read 2 more answers
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