In a bubble sort, you use an inner loop to make pair comparisons.
From the information given, the quickest way to be able to access the information will be C. Go to the FAQ page of the tablet.
<h3>
Solving the research.</h3>
From the complete information, in order to use Photoshop, be should watch a tutorial. When Hannah is setting up her printer but doesn't know where to attach the cables, it's important to read the user's manual.
Also, when Mariana wants an informal research about smartphones, she should read the comments on a vendor bulletin board.
Learn more about researches on:
brainly.com/question/25257437
Answer:
Explanation:
( n cards are there initially )
we pick out the first card in random it takes n-1 comparisons to figure out
its Equivalence card - n-1 steps
Two cards have been eliminated ( this leaves us with 2 and n-2 cards)
we pick out the 2nd card in random it takes n-3 comparisons to figure out
its Equivalence card - n-3 steps
we continue to do this.. till all cards are exhausted ( leaves us with 2
and n-4 cards again)
the last comparison will
have
- n-(n-3)
the sum of all these steps - (n-1) + (n-3) + (n-5) + .........+
(n-(n-3))
if you draw this in the form of a tree.
n - n
2
n-2 - n
2
n-4 - n-2
2
n-6 - n-4
2
n-8 - n- 6
the height of the tree will be log n , sum @ each level is at most n
Answer:
Here you go, Change it however you'd like :)
Explanation:
import random as r
def play_round(p1, p2):
cards = [1,2,3,4,5,6,7,8,9,10,"J","Q","K","A"]
play1 = r.choice(cards)
play2 = r.choice(cards)
while play1 == play2:
play1 = r.choice(cards)
play2 = r.choice(cards)
if cards.index(play1) > cards.index(play2):
return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p1}"
else:
return f"{p1}'s Card: {play1}\n{p2}'s Card: {play2}\nThe Winner is {p2}"
print(play_round("Bob","Joe"))
Answer:it has high coupling
Explanation: Coupling is the property in the field of computer program that is defined as the functions ,data and codes of the program are dependent on each other and cannot be changed independently if requires. Thus,high amount of coupling is not considered as good factor due to high interdependence. Loose coupling can be still permitted.
Other options are correct because name of the class should reflect the purpose and well defined responsibilities should be present, modeling of certain component and high cohesion means keeping similar functions togather is also required. So, the only bad factor is high coupling
