Question

A girl is out jogging at 1.75 m/s and accelerates at 3.29 m/s2 over a displacement of 295 m. What is the girl's final velocity

Answer 1

Answer;

= 44.093 m/s

Explanation;

Using the equation;

v² = u² + 2as; where v is the final velocity, u is the initial velocity, s is the displacement and a is the acceleration.

v² = 1.75² + 2× 3.29 × 295

v² = 1944.1625

v = sqrt 1944.1625

v = 44.093 m/s

The girl's final velocity is 44.093 m/s