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2 years ago

What vaulue of K anwsers the qestion.....K -4 = 1/256 please hurry its the last one i cant fail :(

Mathematics

1 answer:

iogann1982 [59]2 years ago

4 0

K=4+1/256

If this is a multiple choice question, please provide the choices ;)

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Dare to solve it so easy ☺️

qaws [65]

Answer: 1.23×10¹⁶

Step-by-step explanation:

For this problem, we want to use order of operations to solve.

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Let's first solve the parenthesis.

$(9*\frac{999999999}{9+9+9+9+9+9+9+9+9} )^2$ [add denominator]

$(9*\frac{999999999}{81} )^2$ [cross multiply]

$(\frac{999999999}{9} )^2$ [divide]

$(111111111)^2$ [exponent]

1.23×10¹⁶

The ending result is way too large. Therefore, we use scientific notation and get 1.23×10¹⁶.

7 0

2 years ago

WILL GIVE BRAINIEST!!

Snezhnost [94]

Hm let's see the answer should be by the definition of isosceles triangle

7 0

2 years ago

Read 2 more answers

Find the mass of the solid paraboloid Dequals={(r,thetaθ,z): 0less than or equals≤zless than or equals≤8181minus−r2, 0less th

Lubov Fominskaja [6]

Answer:

M = 5742π

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

0 ≤ z ≤ 81 - r^2

0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

$M = \int \int \int {p ( r ,theta, z)} \, dV\\\\$

- We can write the above expression in cylindrical coordinates:

$M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\$

- Perform integration:

$M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\$

$M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] } \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] } \, dtheta\\\\M = 5742\pi kg$

- The mass evaluated is M = 5742π

8 0

2 years ago

Help how do i solve for this ?

Tanya [424]

Answer:

Solution:

Given,

Radius(r) = 11 ft

C = ?

Now,

$c = 2\pi \: r$

C = 2 × 3.14 × 11

= 70 cm

again,

C = 360°

angle = 315°

So,

C = 70 cm

or, 360° = 70 cm

or 1° = 70/360°

or 1° = 7/36

again ,

area = 7/36 × 315°

= 61.25 cm

3 0

2 years ago

zalman started solving 53 times 26 by breaking the problem into parts. Here is what he has done so far 50 times 20=1000 50 times

AfilCa [17]

Answer:

3 * 6 = 18

Step-by-step explanation:

53 * 26 =

= (50 + 3) * (20 + 6)

= 50 * 20 + 50 * 6 + 3 * 20 + 3 * 6

= 1000 + 300 + 60 + 18

Answer: 3 * 6 = 18

5 0

2 years ago