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Alexus [3.1K]
3 years ago
13

Right 1/6 as a decimal​

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0

Answer:

0.1666... would be the real answer

Simora [160]3 years ago
3 0

Answer:

0.166667

Step-by-step explanation:

1/6 = 0.166667

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2y + 3y -3y -6(y + 2) = -y + 6
irinina [24]
The answer is y= -6
my apologies if it’s wrong
8 0
3 years ago
Read 2 more answers
Can someone help me with this please? Thanks! <br><br> Show your work :)
Alexandra [31]
I got 1/81. because u spun the spinner twice i multiplied the regions you are allowed to get by 2 which makes your denominator 18 then you can get the numbers 3 and 6 twice since the spinner is used twice then multiplied them together. so it would be 2/18 x 2/18 = 4/324 which equals 1/81
6 0
4 years ago
A private ship carries two types of cargo: large crates and extra-large crates. Each type of crate weighs a specific amount.
Arisa [49]

Answer:

G. 32

Step-by-step explanation:

32 x 335 = 10720

16,100 - 10720 = 5380/190 = 28.3157894737

275 x 32 = 8800

18,800 - 8800 = 10,000/400 = 25 (This is the closer).

30 x 335 = 10,050

16,100 - 10,050 = 6050/190  = 31.8421052632

30 x 275 = 8250

18,800 - 8250 = 10550/400 = 26.375 (Same reason why it does't work)

25 x 335 = 8375

16,100 - 8375 = 7725/190 = 40.6578947368

25 x 275 = 6875

18,800 - 6875 = 11925/400 = 29.8125

24 x 335 = 8040

16,100 - 8040 = 8060/190 = 42.4210526316

24 x 275 = 6600

18,800 - 6600 = 12200/400 = 30.5

8 0
2 years ago
Can somebody please help answer this word problem using grass method? And showing how u get the answer thanks!!!
siniylev [52]

Answer:

0.25m or 1/4m

Step-by-step explanation:

Given Height of Dorsal Fin = 1/6 of Length of whale Sculpture,

and given length of whale sculpture = 1.5m or 1\frac{1}{2} m\\

Height of Dorsal fin on scuplture = (\frac{1}{6})(1\frac{1}{2} )\\

= (\frac{1}{6} )(\frac{3}{2}) \\= \frac{3}{12} \\= \frac{1}{4}m or 0.25m

5 0
2 years ago
Give me a number between 1 threw 50
Karo-lina-s [1.5K]

Answer: 25

Step-by-step explanation: Your welcome

7 0
3 years ago
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