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Alenkinab [10]
3 years ago
13

I NEED HELP PLEASE!! what is the angle of elevation??

Mathematics
2 answers:
Westkost [7]3 years ago
7 0

Answer:

An object as seen by an observer is the angle between the horizontal and the line from the object to the observer's eye (the line of sight).

Step-by-step explanation:

ira [324]3 years ago
5 0

Answer:

IONK

Step-by-step explanation:

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Is this the correct answer?
Advocard [28]
30kx-6kx=8
24kx=8
x=8/(24k)
x=1/(3k)
so the answer should actually be D
6 0
3 years ago
Add.
kakasveta [241]

To add expressions, you should take note that you can only combine same terms which means they have the same degree of exponents.

-5x^4 + 6x^3 – 43 + 6x^5 – x^2 + 12x + 12

In this expression, you can only combine the constants because they are the only similar terms:

-5x^4 + 6x^3 + 6x^5 – x^2 + 12x + 12 – 43

-5x^4 + 6x^3 + 6x^5 – x^2 + 12x – 31

The standard form starts with the term with the highest exponent so you just have to arrange the terms:

6x^5 - 5x^4 + 6x^3 – x^2 + 12x + 12

 

 

 

5 0
3 years ago
Read 2 more answers
This trapezoid has been divided into two right triangles and a rectangle.
Travka [436]

Answer:

Step-by-step explanation:

the area of the rectangle 168 / the triangle on the left is 12/also the triangle on the right is 12/the area of the trapezoid is 192

8 0
2 years ago
Help me please thank you
Charra [1.4K]

Answer: The answer is y=-2x+5

4 0
4 years ago
Kayden ran 8 km while cayden ran half of distance kayden ran.Isaac ran 1/5 of the distance cayden ran, and jayden ran 1/6 of wha
Darina [25.2K]

Answer:

The difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.

Step-by-step explanation:

The information provided is as follows:

  • Kayden ran 8 km.
  • Cayden ran half of distance Kayden ran.
  • Isaac ran 1/5 of the distance Cayden ran.
  • Jayden ran 1/6 of what Isaac ran.

So, using the given information it can be said that Cayden ran 4 km.

Then the distance Isaac ran is, 4\ \text{km}\times\frac{1}{5}=0.8\ \text{km}.

Then the distance Jayden ran is, 0.8\ \text{km}\times\frac{1}{6}=0.133\ \text{km}

Compute the difference (in km) between what Kayden ran and what Jayden ran as follows:

K-J=8-0.133=7.867

Thus, the difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.

5 0
3 years ago
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