All categories

3 years ago

I NEED HELP PLEASE!! what is the angle of elevation??

Mathematics

2 answers:

Westkost [7]3 years ago

7 0

Answer:

An object as seen by an observer is the angle between the horizontal and the line from the object to the observer's eye (the line of sight).

Step-by-step explanation:

ira [324]3 years ago

5 0

Answer:

IONK

Step-by-step explanation:

You might be interested in

Is this the correct answer?

Advocard [28]

30kx-6kx=8
24kx=8
x=8/(24k)
x=1/(3k)
so the answer should actually be D

6 0

3 years ago

Add.

kakasveta [241]

To add expressions, you should take note that you can only combine same terms which means they have the same degree of exponents.

-5x^4 + 6x^3 – 43 + 6x^5 – x^2 + 12x + 12

In this expression, you can only combine the constants because they are the only similar terms:

-5x^4 + 6x^3 + 6x^5 – x^2 + 12x + 12 – 43

-5x^4 + 6x^3 + 6x^5 – x^2 + 12x – 31

The standard form starts with the term with the highest exponent so you just have to arrange the terms:

6x^5 - 5x^4 + 6x^3 – x^2 + 12x + 12

5 0

3 years ago

Read 2 more answers

This trapezoid has been divided into two right triangles and a rectangle.

Travka [436]

Answer:

Step-by-step explanation:

the area of the rectangle 168 / the triangle on the left is 12/also the triangle on the right is 12/the area of the trapezoid is 192

8 0

2 years ago

Help me please thank you

Charra [1.4K]

Answer: The answer is y=-2x+5

4 0

4 years ago

Kayden ran 8 km while cayden ran half of distance kayden ran.Isaac ran 1/5 of the distance cayden ran, and jayden ran 1/6 of wha

Darina [25.2K]

Answer:

The difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.

Step-by-step explanation:

The information provided is as follows:

Kayden ran 8 km.
Cayden ran half of distance Kayden ran.
Isaac ran 1/5 of the distance Cayden ran.
Jayden ran 1/6 of what Isaac ran.

So, using the given information it can be said that Cayden ran 4 km.

Then the distance Isaac ran is, $4\ \text{km}\times\frac{1}{5}=0.8\ \text{km}$ .

Then the distance Jayden ran is, $0.8\ \text{km}\times\frac{1}{6}=0.133\ \text{km}$

Compute the difference (in km) between what Kayden ran and what Jayden ran as follows:

$K-J=8-0.133=7.867$

Thus, the difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.

5 0

3 years ago