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nika2105 [10]
3 years ago
13

Find 21/25 of $27,000

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
The answer is :22,680
Hope tht helps!
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Sunday later my sister clean 1 3/9 hours Monday my mom clean 2 5/6 hours the my bad clean 1 4/2 hours who cleaned the most
ohaa [14]

Answer:

Hermana

Step-by-step explanation:

4 0
3 years ago
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Translate ƒ(x) = |x| so that it's translated up by 5 units and vertically stretched by a factor of 3. What's the new function g(
zavuch27 [327]

Given:

The parent absolute function is

f(x)=|x|

To find:

The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.

Solution:

The translation is defined as

g(x)=kf(x+a)+b                .... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

Parent function is translated up by 5 units. So, b=5

It is vertically stretched by a factor of 3. So, k=3.

There is no horizontal shift. So, a=0.

Now, putting k=3, a=0 and b=5 in (1), we get

g(x)=3f(x+0)+5

g(x)=3f(x)+5

g(x)=3|x|+5       [\because f(x)=|x|]

Therefore, the correct option is D.

5 0
3 years ago
Senna was having a party for 15 friends. She bought 3 jars of
rodikova [14]

Answer:

chicken

Step-by-step explanation:

cuz im like that

5 0
3 years ago
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How do you graph y=|x|+2
xenn [34]
Make an absolute value function, (coordinates are all (1,1), (2,2), (-5,5) (-1,1) etc.) and shift all the points up by 2 on the y-axis
8 0
3 years ago
I am very stuck with this
Bingel [31]

Answer:

see explanation

Step-by-step explanation:

To multiply the vector by a scalar, multiply each of the elements by the scalar.

To add 3 vectors add the corresponding elements of each vector

2a + 3b + 4c

= 2\left[\begin{array}{ccc}2\\3\\\end{array}\right] + 3\left[\begin{array}{ccc}-4\\1\\\end{array}\right] + 4\left[\begin{array}{ccc}3\\2\\\end{array}\right]

= \left[\begin{array}{ccc}4\\6\\\end{array}\right] + \left[\begin{array}{ccc}-12\\3\\\end{array}\right] + \left[\begin{array}{ccc}12\\8\\\end{array}\right]

= \left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]

= \left[\begin{array}{ccc}4\\17\\\end{array}\right]

8 0
4 years ago
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