Let X be the normal distribution with mean μ=−19
1 answer:
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The given expression is :
2xx+3-5(x-2)
We know that,
Aleena expands 2xx+3-5(x-2) as 2x²+3-5x-10. She is mistaken because the sign before 10 should be +10 instead of -10. Hence, the correct expanded form is 2x²+3-5x+10. Hence, this is the required solution.