3 years ago

Please help me w/ this geometry question. image attached.

Mathematics

1 answer:

patriot [66]3 years ago

7 0

Angle 3 = angle 7 [alternate angles]
=> 4x+1 = 2x + 21
=> 4x-2x = 21-1
=> 2x = 20
=> x = 20/2
=> x = 10

You might be interested in

Help pls i need to knowewwwww

Vladimir [108]

Diameter: 24
radius: 12

3 0

3 years ago

Read 2 more answers

Mark's coach told him that he should

Georgia [21]

Answer:

24 practices in 9 weeks

Step-by-step explanation:

Rate = 8 times / 3 weeks

8 times / 3 weeks * 9 weeks = 24 times

5 0

2 years ago

What is the percent increase from 126 points to 48 points

svetoff [14.1K]

48-126=-78
-78/126= -0.<span>619047619
-0.</span>619047619x100=<span>61.9047619%
This can be rounded to 62%

Hope this helps :)</span>

6 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.

Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

$AC^{2} + BC^{2} = AB^{2}$

$AC^{2} + AD^{2} = AB^{2}$ (Given that AD = BC)

$AC^{2} + AD^{2} = 3^{2}$ (Given that AB=3)

$AC^{2} + AD^{2} = 9$ ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

$AD^{2} + CD^{2} = AC^{2}$

$AD^{2}+(\sqrt{2})^2= AC^{2}$

$AD^{2}+2= AC^{2}$

$AD^{2}=AC^{2} -2$ ...(ii)

Plug value (ii) into (i)

$AC^{2} + AC^{2}-2 = 9$

$2AC^{2} -2=9$

$2AC^{2} =11$

$AC^{2} =\frac{11}{2}$

$AC=\sqrt{\frac{11}{2} }$

Hence final answer is $AC=\sqrt{\frac{11}{2} }$

8 0

3 years ago

Read 2 more answers

Need help with an exam question

stealth61 [152]

Take a pic with phone and it will give u answer

4 0

2 years ago