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dsp73
3 years ago
6

How many terms are in 8y+7z

Mathematics
2 answers:
Schach [20]3 years ago
8 0
Everything separated by a '+' or '-' sign separates a term so in this expression there are 2 terms
Artist 52 [7]3 years ago
7 0
<span>8y+7z
 there are 2 terms.
hope it helps</span>
You might be interested in
Given the system of equations 2 x − 3 y − 9 z = 9 x + 3 z = 3 − 3 x + y − 4 z = − 10 (a) determine whether the system is inconsi
Wewaii [24]

Answer:

Dependent

x=3-3z

y=-5z-1

Step-by-step explanation:

We are given that system of equations

2x-3y-9z=9 (Equation I)

x+3z=3 ( Equation II)

-3x+y-4z=-10 (Equation III)

Equation III multiply by 3 and then add to equation I then we get

-7x-21z=-21

Divided by -7 then we get

x+3z=3

Now , obtained equation subtract from equation II then we get

0=0

Hence, equation II is a linear combination of equation I and equation III.

Therefore, system is dependent because system has infinite solutions.

x=3-3z

Substitute the value of x in equation I then we get

2(3-3z)-3y-9z=9

6-6z-3y-9z=9

3y=-15z+6-9=-15z-3

y=-5z-1

3 0
3 years ago
Compare the variation in heights to the variation in weights of thirteen-year old girls. The heights 17) (in inches) and weights
Travka [436]

Answer:

Height = 4.3%

Weight = 16.8%

There is substantially more variation in the weights than in the heights of the girls.

Step-by-step explanation:

The heights of the girls in inches

58.7 61.4 62.1 64.7 60.1 58.3 64.6 63.7 66.1

The weight of the girls in pounds

89 97 93 119 96 90 123 98 139

Before we start calculation for variations, we first find the means

The mean height = (Σx)/N

The average is the sum of variables divided by the number of variables

x = each height

N = number of girls sampled = 9

Mean height = (58.7+61.4+62.1+64.7+60.1+58.3+64.6+63.7+66.1)/9

Mean height = (559.7/9)

Mean height = 62.2 inches

The standard deviation is the square root of variance. And variance is an average of the squared deviations from the mean.

Mathematically,

Standard deviation = σ = √[Σ(x - xbar)²/(N-1)]

x = each variable

xbar = mean = 62.2

N = number of variables

Σ(x - xbar)² = [(58.7-62.2)² + (61.4-62.2)² + (62.1-62.2)² + (64.7-62.2)² + (60.1-62.2)² + (58.3-62.2)² + (64.6-62.2)² + (63.7-62.2)² + (66.1-62.2)²] = 56.94

σ = √(56.94/8) = √(7.1175)

σ = 2.67 inches

Variation in terms of the mean = (2.67/62.2) = 0.0429 = 4.3%.

For the weights,

we first find the means

The mean weight = (Σx)/N

The average is the sum of variables divided by the number of variables

x = each weight

N = number of girls sampled = 9

Mean height = (89+97+93+119+96+90+123+98+139)/9

Mean height = (944/9)

Mean height = 104.9 pounds

The standard deviation is the square root of variance. And variance is an average of the squared deviations from the mean.

Mathematically,

Standard deviation = σ = √[Σ(x - xbar)²/(N-1)]

x = each variable

xbar = mean = 104.9

N = number of variables

Σ(x - xbar)² = [(89-104.9)² + (97-104.9)² + (93-104.9)² + (119-104.9)² + (96-104.9)² + (90-104.9)² + (123-104.9)² + (98-104.9)² + (139-104.9)²] = 2,494.89

σ = √(2,494.89/8) = √(311.86)

σ = 17.66 pounds

Variation in terms of the mean = (17.66/104.9) = 0.168 = 16.8%

7 0
3 years ago
Two teaching methods and their effects on science test scores are being reviewed. A random sample of 18 students, taught in trad
Leona [35]

Answer:

the value of the t test statistic is - 3.419

Step-by-step explanation:

Given that;

n₁ = 18, u₁ = 78.3, s₁ = 6.4

n₂ = 11, u₂ = 84.3, s₂ = 5.3

α = 0.1

Now The hypothesis are;

H₀ : u₁ = u₂

H₁ : u₁ < u₂

To compute the value of the t test statistic;

t = [(x₁ - x₂) / s × √(1/n₁ + 1/n₂)]

where

s = √ [ ((n₁-1) × s₁² + (n₂ - 1 ) × s₂²) / ( n₁ + n₂ - 2)]

s = √ [ ((18-1) × 6.4² + (11 - 1 ) × 5.3²) / ( 18 + 11 - 2)]

s = √ [ (7 × 40.96 + 10 × 28.09 ) / 27 ]

s = √ [ (286.72 + 280.9) / 27 ]

s = √(567.62/27)

s = √21.0229

s = 4.585

Now  t test statistics t = [(x₁ - x₂) / s × √(1/n₁ + 1/n₂)]

t = [(78.3 - 84.3) / 4.585 × √(1/18 + 1/11)]

t = -6 / (4.585 × 0.3827)

t = - 6 / 1.7546795

t = - 3.419

Therefore the value of the t test statistic is - 3.419

as as level of significance α  = 0.1

df = 18+11-2 = 27

∴ T(csal) = t(0.1, 27) = -1.313

That is

t(statistics) < t(cal)

{ - 3.419  < -1.313 }

5 0
3 years ago
13+5-7 is what percent
ANEK [815]
"Addition, Subtraction,
Which ever comes first!" ~ my teacher


13+5-7
^
18-7
^
11%

^
11%


7 0
3 years ago
Which expressions can never result in a negative real number when evaluated for any value of x? Selecta
Y_Kistochka [10]
I think it’s is 5 and take it’s now
8 0
3 years ago
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