Question

A volleyball player hit a ball with a mass of 0.25 kg. The average acceleration of the ball is (15.5m/s to the 2nd power). How much force did the volleyball player apply to the ball?

Answer 1

Using the Newton's second Law

F≠0
F=ma

m= 0.25 kg
a= 15.5 m/s

F=ma
F=(.25)(15.5)
F=3.875 N

Ta daa!
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PS this would be better suited to the "Physics" section

Answer 2

3.87 N I did the test and get it right