Let's find the discriminant of <span>x^2+9x+14=0. Here, a=1, b=9 and c=14.
The discriminant is b^2-4ac. Substituting the above numeric values,
9^2-4(1)(14) = 81-56 = 25
The sqrt of 25 is 5. Thus, your polynomial has two unequal, real roots.
Off the point example: If the discriminant were zero, your poly would have two real, equal roots.</span>
Answer:
okay thanks for letting me know
Step-by-step explanation:
Answer:
The answer is 9x² - 6x - 1
Step-by-step explanation:
∵ (6x³ + x² - 10x - 1) - (6x³ - 8x² - 4x) =
0 + 9x² - 6x - 1 = 9x² - 6x - 1