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3 years ago

2+7347 and much is it

Mathematics

2 answers:

Lana71 [14]3 years ago

4 0

7349 that's the answer and really? That was easy

Triss [41]3 years ago

4 0

2 + 7,347 = 7,349
All you have to do is add 2 and 7,347
So the answer is 7,349, hope it helped : )

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Management selection. A corporation plans to fill 2 different positions forâ€‹ vice-president, Upper V 1 and Upper V 2â€‹, from

Mandarinka [93]

Answer:

45 different ways to fill the positions.

Step-by-step explanation:

Consider the provided information.

Management selection. A corporation plans to fill 2 different positions for vice-president, V₁ and Upper V₂, from administrative officers in 2 of its manufacturing plants. Plant A has 9 officers and plant B has 5.

We need to find the probability that 2 positions be filled if the Upper V₁ position is to be filled from plant A and the Upper V₂, position from plant B?

To fill the post of V₁ from plant A, which has 9 officers, we have 9 ways.

To fill the post of V₂ from plant B, which has 5 officers, we have 5 ways.

Therefore, the total number of ways are: $9\times 5=45$

Hence, 45 different ways to fill the positions.

8 0

4 years ago

On a website, listeners rate music from 1 star to 5 stars. One song was rated 1 star by 3.5% of the listeners. There were 49 lis

defon

Answer:

1400

Step-by-step explanation:

3.5% of listeners rated the song as 1 star

49 listeners rated the song as 1 star

49 listeners = 3.5% of listeners

we want to find 100% of listeners. we can do this by multiplying both sides of the equation by 100/3.5, getting one side to 100% and the other to what it is equal to

49 * 100/3.5 listeners = 100% of listeners = 1400

3 0

3 years ago

6 people go eat some order chicken dinner for $14 and some order steak dinner for $17. If the total bill was $99, how many peopl

White raven [17]

Answer:

5 people bought the $17 steak and 1 person bought the $14 chicken.

Step-by-step explanation:

7 0

3 years ago

Show that an integer is divisible by 11 if and only if the alternating sum (add first digit, subtract the second, add the third,

Bess [88]

Answer and Step-by-step explanation:

Suppose that we have a number y which is a positive integer and that:

y = $x_n...x_5x_4x_3x_2x_1x_0$

Where;

$x_{0}$ = digit at 10⁰ => one's place (units place)

$x_1$ = digit at 10¹ => 10's place (tens place)

$x_{2}$ = digit at 10² => 100's place (hundreds place)

$x_{3}$ = digit at 10³ => 1000's place (thousands place)

$x_{n}$ = digit at 10ⁿ place

Then;

y = $x_{0}$ * 10⁰ + $x_1$ * 10¹ + $x_{2}$ * 10² + $x_{3}$ * 10³ + $x_{4}$ * 10⁴ + $x_5$ * 10⁵ + . . . + $x_{n}$ * 10ⁿ

Since 10⁰ = 1, let's rewrite y as follows;

y = $x_{0}$ + $x_1$ * 10¹ + $x_{2}$ * 10² + $x_{3}$ * 10³ + $x_{4}$ * 10⁴ + $x_5$ * 10⁵ + . . . + $x_{n}$ * 10ⁿ

Now, to test if y is divisible by 11, replace 10 in the equation above by -1. Since 10 divided by 11 gives -1 (mod 11) [mod means modulus]

y = $x_{0}$ + $x_1$ * (-1)¹ + $x_{2}$ * (-1)² + $x_{3}$ * (-1)³ + $x_{4}$ * (-1)⁴ + $x_5$ * (-1)⁵ + . . . + $x_{n}$ * (-1)ⁿ

=> y = $x_{0}$ - $x_1$ + $x_{2}$ - $x_{3}$ + $x_{4}$ - $x_5$ + . . . + $x_{n}$ (-1)ⁿ (mod 11)

Therefore, it can be seen that, y is divisible by 11 if and only if alternating sum of its digits $x_{0}$ - $x_1$ + $x_{2}$ - $x_{3}$ + $x_{4}$ - $x_5$ + . . . + $x_{n}$ (-1)ⁿ is divisible by 11

Let's take an example

Check if the following is divisible by 11.

i. 1859

Solution

1859 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (1 - 8 + 5 - 9) is divisible by 11.

1 - 8 + 5 - 9 = -11.

Since -11 is divisible by 11 so is 1859

ii. 31415

Solution

31415 is divisible by 11 if and only if the alternating sum of its digit is divisible by 11. i.e if (3 - 1 + 4 - 1 + 5) is divisible by 11.

3 - 1 + 4 - 1 + 5 = 10.

Since 10 is not divisible by 11 so is 31415 not divisible.

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4 years ago

I need more help! how do I do this?

adoni [48]

Bottom left

Step-by-step explanation:x is not defined between 0 and 2 (there’s a definition for x<0 and another for x>=2) so there needs to be no y or x values between x =0 and x=2. This is only true for the bottom left

6 0

2 years ago