All categories

2 years ago

2+7347 and much is it

Mathematics

2 answers:

Lana71 [14]2 years ago

4 0

7349 that's the answer and really? That was easy

Triss [41]2 years ago

4 0

2 + 7,347 = 7,349
All you have to do is add 2 and 7,347
So the answer is 7,349, hope it helped : )

You might be interested in

PLEASE Help!!!

andrew-mc [135]

25% is the percent increase

8 0

2 years ago

Which of the following is an X-intercept of the function f(X)=X^3-5X^2-8X+48

Anton [14]

You have to searh the x values that make f(x) = 0

Factoring this equation is very difficult.

You can divide by x+3 and you will find that the equation can be factored as

(x+3)(x-4)^2

That means that x = -3 and x = 4 make f(x) = 0

Then the points are (-3,0) and (4,0).

6 0

3 years ago

What is the area of a triangle whose side is 17 meters long

Lunna [17]

Answer:

125.141

Step-by-step explanation:

Assuming that this is an equilateral triangle, I am going to divide this triangle in half to get a right triangle.

17 is our hypotenuse

17/2 = 8.5, this is one of our legs

The other leg is our height, which we will find.

We use Pythagoras Theorem to find the height/leg: $a^{2} +b^{2} =c^{2}$

$17^{2} -8.5^{2} = 216.75$

$\sqrt{216.75}$ = 14.72243186

Now, we use another formula to find the area of the triangle: $\frac{Base*Height}{2}$

14.72243186 × 17 = 250.2813416

250.2813416 ÷ 2 = 125.1406708

8 0

3 years ago

What is ? algebra 2

Alexxx [7]

(?) = (x - 3)(x + 3)

Step-by-step explanation:

[Attached]

4 0

2 years ago

Ex 2.8 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1

harkovskaia [24]

$y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\
y''(0)=20\cdot0^3=0$

The value of the second derivative for $x=0$ is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of $5x^4$ is always positive for $x\in\mathbb{R}\setminus \{0\}$ . That means at $x=0$ there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval $[-2,1]$ .
The function $y$ is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

$y_{max}=y(1)=1^5-3=-2$

4 0

3 years ago