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2 years ago

What is the answer to this problem

Mathematics

1 answer:

sveticcg [70]2 years ago

5 0

I believe the answer 86

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Which is the correct stem-and-leaf plot for the data set.

jasenka [17]

Answer:

I just FINISHED THESE QUESTIONS

Step-by-step explanation:

but which plot

7 0

2 years ago

The diagram shows a prism.

telo118 [61]

Answer:

Total surface area of the prism = 920 cm²

Step-by-step explanation:

Given prism has 2 similar triangular surfaces and 3 rectangular surfaces of different dimensions.

Area of one triangular side = $\frac{1}{2}(\text{Base})(\text{Height})$

Area of 2 similar sides = Base × Height

= 8 × 15

= 120 cm²

Area of rectangular side with dimensions 17cm × 20cm

Area of the side = 17 × 20 = 340 cm²

Area of the second rectangular side with dimensions 8cm × 20cm

Area of the side = 8 × 20 = 160 cm²

Area of third rectangular side with dimensions 20cm × 15cm

Area of the side = 20 × 15 = 300 cm²

Total surface area of the given triangular prism = 120 + 340 + 160 + 300

= 920 cm²

6 0

2 years ago

A rectangular box with a square base is to be constructed from material that costs $9 per ft2 for the bottom, $5 per ft2 for the

kramer

Answer:

$18.73ft^3$

Step-by-step explanation:

Let

Side of square base=x

Height of rectangular box=y

Area of square base=Area of top= $(side)^2=x^2$

Area of one side face= $l\times b=xy$

Cost of bottom=$9 per square ft

Cost of top=$5 square ft

Cost of sides=$4 per square ft

Total cost=$204

Volume of rectangular box= $V=lbh=x^2y$

Total cost= $9(x^2)+5x^2+4(4xy)=14x^2+16xy$

$204=14x^2+16xy$

$204-14x^2=16xy$

$y=\frac{204-14x^2}{16x}=\frac{102-7x^2}{8x}$

Substitute the values of y

$V(x)=x^2\times \frac{102-7x^2}{8x}=\frac{1}{8}(102x-7x^3)$

Differentiate w.r.t x

$V'(x)=\frac{1}{8}(102-21x^2)=0$

$V'(x)=0$

$\frac{1}{8}(102-21x^2)=0$

$102-21x^2=0$

$102=21x^2$

$x^2=\frac{102}{21}=4.85$

$x=\sqrt{4.85}=2.2$

It takes positive because side length cannot be negative.

Again differentiate w.r. t x

$V''(x)=\frac{1}{8}(-42x)$

Substitute the value

$V''(2.2)=-\frac{42}{8}(2.2)=-11.55$

Hence, the volume of box is maximum at x=2.2 ft

Substitute the value of x

$y=\frac{102-7(2.2)^2}{8(2.2)}=3.87 ft$

Greatest volume of box= $x^2y=(2.2)^2\times 3.87=18.73 ft^3$

5 0

3 years ago

2. Find the product.<br> 7.85 X 4.07 =

Novosadov [1.4K]

Answer:

7.85

4.07

---------------=

31.9495

8 0

2 years ago

At which x-value does the cosine function attain a maximum value?

Liono4ka [1.6K]

9514 1404 393

Answer:

x = 0

Step-by-step explanation:

It can help to keep a graph of the cosine function in mind. It starts off at its maximum value at x = 0.

7 0

2 years ago