All categories

3 years ago

X = 5 -3 x is not quadratic what is the reason

Mathematics

2 answers:

Lyrx [107]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

A quadratic has a squared variable , this equation does not

The general form of a quadratic equation is

ax² + bx + c = 0 ( a ≠ 0 )

The equation here

x = 5 - 3x ( add 3x to both sides )

4x = 5 is not in quadratic form and is a linear equation, since the variable is x not x²

OleMash [197]3 years ago

6 0

Answer:Although the Quadratic Formula always works as a strategy to solve quadratic equations, for many problems it is not the most efficient method. Sometimes it is faster to factor or complete the square or even just "out-think" the problem. For each equation below, choose the method you think is most efficient to solve the equation and explain your reason. Note that you do not actually need to solve the equation. a. x2+7x−8=0x

+7x−8=0, b. (x+2)2=49(x+2)

=49, c. 5x2−x−7=05x

−x−7=0, d. x2+4x=−1x

+4x=−1.

You might be interested in

What equation represents the linear equation shown in the graph? Enter your answer in the box. Write your answer in the form y =

leonid [27]

It would be y = -1/4x + 4

5 0

3 years ago

Read 2 more answers

I need help !!!! Please

timofeeve [1]

The answer would be 4.5

6 0

3 years ago

Anyone know the right answer?

alekssr [168]

7/63=1/9 acres per pound of seeds
3/6=1/2 pound flour per dollar

3 0

3 years ago

Secret Decimal Number Riddle<br> I have 2 ones 22 hundredths 12 tenths <br> What number am I?

Ann [662]

3.22 is the correct answer

6 0

3 years ago

What is the area of the space

Nikitich [7]

check the picture below.

since we know is a rectangle, then we can simply find a width and a length, say hmmm CD and CB and get their product, recall that the area of a rectangle is width*length.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ C(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad D(\stackrel{x_2}{-7}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ CD=\sqrt{[-7-(-4)]^2+[1-(-3)]^2}\implies CD=\sqrt{(-7+4)^2+(1+3)^2} \\\\\\ CD=\sqrt{(-3)^2+4^2}\implies CD=\sqrt{9+16}\implies \boxed{CD=5}\\\\ -------------------------------$

$\bf C(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) \\\\\\ CB=\sqrt{[4-(-4)]^2+[3-(-3)]^2}\implies CB=\sqrt{(4+4)^2+(3+3)^2} \\\\\\ CB=\sqrt{8^2+6^2}\implies CB=\sqrt{64+36}\implies \boxed{CB=10}\\\\ -------------------------------\\\\ \stackrel{\textit{area of rectangle}}{CD\cdot CB}\implies 50$

4 0

3 years ago

X = 5 -3 x is not quadratic what is the reason​

X = 5 -3 x is not quadratic what is the reason