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Schach [20]
2 years ago
8

An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle

above?

Mathematics
1 answer:
omeli [17]2 years ago
4 0

Answer:

\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}

The middle point of the base is placed at point

\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i

The length of the height is the distance between the points 5+9i and 7+3i

\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}

So, the area of the triangle is

A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

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Answer:

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Step-by-step explanation:

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Answer:

(0.5, 1.3)(0.5, 1.3)

Step-by-step explanation:

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As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

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