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nasty-shy [4]
3 years ago
13

On which graph does the red point have a clear meaning?

Mathematics
2 answers:
Feliz [49]3 years ago
6 0

Answer:

It is A, the bird feeder image.

Step-by-step explanation:

First of all, the middle image shows the red dot as having multiple values with the same y-coordinate. The first answer states that the third image is incorrect. Next of all, process of elimination states that if the middle and the last answer isn't the correct one, it is the first picture.

Kobotan [32]3 years ago
4 0

Answer:

The graph where the red point has a meaning is the graph C or third graph.

Step-by-step explanation:

As we can see the first and second graphs are irrelevant and have no relation between the x axis and y axis.

In graph A, the bird feeder graph is shown where the quart is a unit for liquids and pounds is a unit for solids. Thus, the red point cannot be defined.

Similarly, in graph B, height and team numbers are not related to each other in any way, so not clear meaning can be withdrawn here,

In graph C, the relation between cost of pictures and number of pictures are shown. We can very well understand here, that as the number of pictures increases, the cost increases.

So, the graph where the red point has a meaning is the graph C or third graph.

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Ball bearings are manufactured with a mean diameter of 5 millimeters(mm). Because of variability in the manufacturing process, t
dexar [7]

Answer:

a) 0.0668 of ball bearings have a diameter more than 5.03 mm

b) 0.0124 of ball bearings will be discarded

c) The plant manager should expect to discard 372 balls.

d) 57,710 ball bearings should be manufactured.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 5, \sigma = 0.02

(a) What proportion of ball bearings has a diameter more than 5.03 mm?

This is 1 subtracted by the pvalue of Z when X = 5.03. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.03 - 5}{0.02}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 of ball bearings have a diameter more than 5.03 mm

(b) Any ball bearings that have a diameter less than 4.95 mm or greater than 5.05 mm are discarded. What proportion of ball bearings will be discarded?

Lower than 4.95 or greater than 5.05. Both these proportions are the same, so we find one of them, and multiply by 2.

Less than 4.95:

pvalue of Z when X = 4.95. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.95 - 5}{0.02}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062

2*0.0062 = 0.0124

0.0124 of ball bearings will be discarded.

(c) Using the results of part (b), if 30,000 ball bearings are manufactured in a day, how many should the plant manager expect to discard?

0.0124 of 30,000. So

0.0124*30000 = 372

The plant manager should expect to discard 372 balls.

(d) If an order comes in for 50,000 ball bearings, how many bearings should the plant manager manufacture if the order states that all ball bearings must be between 4.97 mm and 5.03 mm?

Proportion of bearings between 4.97 mm and 5.03 mm:

pvalue of Z when X = 5.03 subtracted by the pvalue of Z when X = 4.97. So

X = 5.03

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.03 - 5}{0.02}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 4.97

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.97 - 5}{0.02}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.9332 - 0.0668 = 0.8664 of ball bearings will have adequate proportions. So 0.8664 of x should be 50,000. then

0.8664x = 50000

x = \frac{50000}{0.8664}

x = 57 710

57,710 ball bearings should be manufactured.

3 0
3 years ago
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