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Eddi Din [679]
3 years ago
11

Rewrite the product in exponential form: a.a.a.b.b.b.b

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0
It would be a³ b ^4.

Hope This Helps You!
Good Luck Studying :)
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How much greater is the mass of Can A than Can B? cola cola B Con A: 20 grams Can B: 480 grams 360 grams 340 grams 240 grams 260
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I would say 340 grams........

Step-by-step explanation:

340 grams

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Twice a year, the P.E. teachers test the fitness level of all sixth grade students at Walker Middle School. The students' weight
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8 2 − 6(7 − 4) + 2 simplified
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82 - 6(7 - 4) + 2 \\  82 - 6(3) + 2 \\ 82 - 18 + 2 \\ 64 + 2 \\ 66

<h3><em>i </em><em>hope</em><em> it</em><em> helps</em><em> u</em><em> ☠️</em></h3>
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]
Kamila [148]

Use the power rule for differentiation:

\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)

You can use this formula if you remember that a root is just a rational exponential:

\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}

So, remembering that the derivative of the logarithm is 1/x, you have

\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}

Which you can rewrite as

\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}

3 0
3 years ago
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