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Usimov [2.4K]
3 years ago
12

Solve for x on this problem please

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

x = -3

Step-by-step explanation:

The LCD is 6, so multiply both sides by 6.

6[(3x + 1)/2] - 6[(4x - 3)/3] = 6 * 1

3(3x + 1) - 2(4x - 3) = 6

9x + 3 - 8x + 6 = 6

x + 9 = 6

x = -3

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a bakery used 3 cups of flour to make a full size cake if they wanted to make a cake that was 1/2 the size how many cups of flou
Anastasy [175]

1 cup 4oz.  1 cup = 8oz

4 0
4 years ago
Find the 16th term of the arithmetic sequence whose common difference is d=6 and whose first term is a1=1.
sertanlavr [38]

Answer:

The 16th term is 91

Step-by-step explanation:

The 16th term is U16 given by

U16=a+(n-1)d

U16=1+(16-1)×6

U16=1+(15×6)

U16=91

4 0
3 years ago
The area of the regular octagon is approximately 54 cm2. What is the length of line segment AB, rounded to the nearest tenth?
erastova [34]

Answer:

AB = 3.3 cm

Step-by-step explanation:

The formula to find out area of a regular octagon is given by

A=2(1+\sqrt{2})a^{2}

where a is the length of each side of the regular octagon.

Plugin A=54 into the formula

54=2(1+\sqrt{2})a^{2}

Divide both sides by 2

\frac{54}{2} =\frac{2}{2} (1+\sqrt{2})a^{2}

27 = (1+\sqrt{2})a^{2}

Plugin √2 as 1.41

27 = (1+1.41)a^{2}

27 = (2.41)a^{2}

Divide both sides by 2.41

\frac{27}{2.41} = \frac{2.41}{2.41} a^{2}

11.20 = a^{2}

Taking square root on both sides

\sqrt{11.20}  = \sqrt{a^{2}}

a = 3.346

a = 3.3 cm (rounded to nearest tenth)

so, length of side AB = 3.3 cm

6 0
3 years ago
Read 2 more answers
X + 14 = 26, x = <br><br>I need help please​
xxMikexx [17]

x=12

hope this helps :))

3 0
3 years ago
Read 2 more answers
What is the result of 4 /<br> 8/12?<br><br> Please help I need it<br><br><br> And thank you
Vitek1552 [10]

Answer:

6

Step-by-step explanation:

The 4 and 12 are multiplied together which creates 48 (4*12). Then you divide the 48 by 8 (48/8) wich equals 6.

4 0
4 years ago
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