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3 years ago

Solve for x on this problem please

Mathematics

1 answer:

iren2701 [21]3 years ago

6 0

Answer:

x = -3

Step-by-step explanation:

The LCD is 6, so multiply both sides by 6.

6[(3x + 1)/2] - 6[(4x - 3)/3] = 6 * 1

3(3x + 1) - 2(4x - 3) = 6

9x + 3 - 8x + 6 = 6

x + 9 = 6

x = -3

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Help me plz!!!!!!! test tomorrow

Alex

Answer:

The number of movies purchased is 5

Step-by-step explanation:

40.00 + 3.50 = 43.50

43.50 + 3.50 = 47.00

47.00 + 3.50 = 50.50

50.50 + 3.50 = 54.00

54.00 + 3.50 = 57.50

so if you add 3.50 to 40, 5 times you'll get 57.50

Hope it helped

7 0

3 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0

3 years ago

What is the product of 2•2

lisabon 2012 [21]

Answer:

Step-by-step explanation:

2*2 can be modeled using the following.

2 rows of 2

| |

Total 4 sticks

7 0

3 years ago

Write this in equation form 5 less than risk equal to 16

dolphi86 [110]

Risk - 5 = 16. It is just mathematical language.

7 0

3 years ago

A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take

muminat

Answer:

The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill (Du) = 2 miles

The time taken by jogger in downhill (Td) = T hour

The time taken by jogger in uphill (Tu) = T hour

Let The speed of jogger in uphills (Su) = x mph

So ,The speed of jogger in downhills (Sd) =( x + 6 ) mph

∵, Time = $\frac{Distance}{Speed}$

So, Tu = $\frac{Du}{Su}$

Or, T = $\frac{2}{x}$ h

And Td = $\frac{Dd}{Sd}$

Or, T = $\frac{5}{(x + 6)}$ h

∵ Time duration of both is same

∴ $\frac{2}{x}$ = $\frac{5}{(x + 6)}$

Or, 2 × (x + 6) = 5x

Or, 2x + 12 = 5x

So, 12 = 3x

∴ x = $\frac{12}{3}$ = 4 mph

And x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour Answer

5 0

3 years ago