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Helga [31]
3 years ago
15

I need help -Geometry

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Step-by-step explanation:

We apply the pythagorean theorem on ABC.

AC^2=11^2+60^2 = 3600 + 121 = 3721

AC=61

Which means that sin(BAC) = 60/61.

However, sin^2(BAC) + cos^2(BAC)=1.

3600/3721 + cos^2(BAC) = 3721/3721.

cos^2(BAC) = 121/3721.

BAC is an acute angle so the cos is a positve number.

cos(BAC) = 11/61.

Lastly, x/60 = cos(BAC), so x= 660/61

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Answer:

A?

Step-by-step explanation:

If the square was split into 3 rectangles the 3 rectangles sum up to the square.

4 0
2 years ago
(x2−1)(x+1)≥0. pls help me​
docker41 [41]

Step-by-step explanation:

(x²-1)(x+1)≥0

As it has two multiples,

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Answer:

= 5x -10

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=(3)(3x)+(3)(−4)+(−2)(2x)+(−2)(−1)

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=9x+−12+−4x+2

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3 0
3 years ago
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Solve for X 4x-5=2x+3
Phantasy [73]
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Area of a trapezium is 31.5cm. If the parallel sides are of lengths 7.3cm and 5.3cm. Calculate the perpendicular distance betwee
Anna11 [10]

Answer:

5cm

Step-by-step explanation:

Given area of trapezium = 31.5 sq. cm

Length of parallel sides = 7.3cm and 5.3cm

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1/2*(sum of parallel sides)*perpendicular distance between parallel sides

sum of parallel sides =  (7.3 + 5.3) = 12.6cm

substituting value of area given and sum of parallel sides we have

31.5 = 1/2* 12.6 * perpendicular distance between parallel sides

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perpendicular distance between parallel sides = 63/12.6 = 5

Therefore perpendicular distance between parallel sides for given trapezium is 5cm.

5 0
3 years ago
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