Answer: x= -189, y =252
Step-by-step explanation:
Let the first number be x and second number be y
so
x + y = 63
x = 63-y
now
1/9 of x + 1/6 of y = 21
x/9 + y/6 = 21
substituting x's value from equation i
(63-y)/9 + y/6 = 21
(378-6y+9y)/54 = 21
378+3y = 1134
3y = 1134-378
so, 3y = 756
so, y = 756/3
so, y = 252
now
x = 63-252
so, x = -189
The last one (0,0) the middle of the graph is always (0,0)
Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Answer:
Step-by-step explanation:
Split it into two:
Y<3x
Y<5
X = 1
Y = 3
(1,3)
X = 2
Y = 6
(2, 6)
Plot the line up to y = 4.999999999999999999999 and not higher.
