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Zigmanuir [339]
3 years ago
9

Label the vertices and state the Pythagorean Theorem for the following right triangle. Find x.

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

Pythagorean Theorem Statement is below.

Therefore the value of x is 9 m.

Step-by-step explanation:

Given:

Label the vertices as A , B , C shown in figure below such that

∠A = 90°

AC = Longer leg = 12 m

AB = Shorter leg = x

BC = Hypotenuse = 15 m

To Find:

x = ?

Solution:

Pythagorean Theorem :

Pythagorean Theorem States that "the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides".

Which can be Written as

(\textrm{Hypotenuse})^{2} = (\textrm{One Side})^{2}+(\textrm{Other Side})^{2}

OR

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

i.e (BC)^{2}=(AB)^{2}+(AC)^{2}

Substituting the values AB ,AC, BC we get

(15)^{2}=(x)^{2}+(12)^{2}\\(x)^{2}=225-144=81\\(x)^{2}=81\\Square\ Rooting\\x=\sqrt{81}=9\\x=9\ m

Therefore the value of x is 9 m.

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frez [133]

Problem 1

<h3>Answer: False</h3>

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Explanation:

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f( g(x) ) = 6x+1 ... plug in g(x) = 6x

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Now let's flip things around

g(x) = 6x

g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)

g( f(x) ) = 6(x+1) .... plug in f(x) = x+1

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This shows that (f o g)(x) = (g o f)(x)  is a false equation for the given f(x) and g(x) functions.

===============================================

Problem 2

<h3>Answer: True</h3>

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Explanation:

Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.

For example, let

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The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.

So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).

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