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Zigmanuir [339]
3 years ago
9

Label the vertices and state the Pythagorean Theorem for the following right triangle. Find x.

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

Pythagorean Theorem Statement is below.

Therefore the value of x is 9 m.

Step-by-step explanation:

Given:

Label the vertices as A , B , C shown in figure below such that

∠A = 90°

AC = Longer leg = 12 m

AB = Shorter leg = x

BC = Hypotenuse = 15 m

To Find:

x = ?

Solution:

Pythagorean Theorem :

Pythagorean Theorem States that "the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides".

Which can be Written as

(\textrm{Hypotenuse})^{2} = (\textrm{One Side})^{2}+(\textrm{Other Side})^{2}

OR

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

i.e (BC)^{2}=(AB)^{2}+(AC)^{2}

Substituting the values AB ,AC, BC we get

(15)^{2}=(x)^{2}+(12)^{2}\\(x)^{2}=225-144=81\\(x)^{2}=81\\Square\ Rooting\\x=\sqrt{81}=9\\x=9\ m

Therefore the value of x is 9 m.

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It would take Charlie 7 hours to drive 504 miles. 
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3 years ago
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ana wants to earn 88 percent in her chemistry class she has one quiz left to take on the first 5 quizzes she received a 74 perce
Alinara [238K]

Answer: 91

Step-by-step explanation: I assume you had a typo and mean what did Ana need on the 5th quiz since you only listed 4 quiz scores.

(74 + 92 + 83 + 100 + x)/5 = 88

(349 + x)/5 = 88

((349 +x)/5) x 5 = 88 x 5

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x  = 91

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3 years ago
Why dose a triangle form 180 degress
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3 years ago
A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​
Luden [163]

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = 1 *10^6 bytes

kilobyte = 1*10^3 bytes

and a regular byte would just be 1

Now, you will need to do a conversion:

1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 1*10^6 bytes!)

In the second fraction thought, remember one kilobyte is 1*10^3 bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do \frac{1kilobyte}{1*10^3bytes}, but I think it is more correct to do write it out how I did).

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Now, your answer should be:

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6 0
3 years ago
Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}

3 0
3 years ago
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