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castortr0y [4]
3 years ago
14

In a class 30 of students, 19 play an instrument and 10 play a sport. There are 8

Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

1/30

Step-by-step explanation: There are 30 students 19 play instr, 10 play spor,

8 who do both. Their is one student that was left out so the answer is 1/30

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Is the measure of In the diagram below , overline XY and are tangent to A. 90 B. 180 C. 100 D. 130
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Answer:

C can i have brainlest pls

Step-by-step explanation:

4 0
2 years ago
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Evaluate (tan 60)(cos 45)
loris [4]

Answer: the tan. Of 60 is .3200

The cos. Of 45 is .5253

Hope this helps :)

Step-by-step explanation:

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Taya2010 [7]
X + 2y = -4
-x            -x

2y   = -x - 4

Divide all by 2

y = -x/2 - 2

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Given that tan θ ≈ −0.087, where 3 2 π < θ < 2 , π find the values of sin θ and cos θ.
elena-s [515]

Answer:

  • sin θ ≈ -0.08667
  • cos θ ≈ 0.99624

Step-by-step explanation:

Straightforward use of the inverse tangent function of a calculator will tell you θ ≈ -0.08678 radians. This is an angle in the 4th quadrant, where your restriction on θ places it. (To comply with the restriction, you would need to consider the angle value to be 2π-0.08678 radians. The trig values for this angle are the same as the trig values for -0.08678 radians.)

Likewise, straightforward use of the calculator to find the other function values gives ...

  sin(-0.08678 radians) ≈ -0.08667

  cos(-0.08678 radians) ≈ 0.99624

_____

<em>Note on inverse tangent</em>

Depending on the mode setting of your calculator, the arctan or tan⁻¹ function may give you a value in degrees, not radians. That doesn't matter for this problem. sin(arctan(-0.087)) is the same whether the angle is degrees or radians, as long as you don't change the mode in the middle of the computation.

We have shown radians in the above answer because the restriction on the angle is written in terms of radians.

_____

<em>Alternate solution</em>

The relationship between tan and sin and cos in the 4th quadrant is ...

  \cos{\theta}=\dfrac{1}{\sqrt{1+\tan^2{\theta}}}\\\\\sin{\theta}=\dfrac{\tan{\theta}}{\sqrt{1+\tan^2{\theta}}}

That is, the cosine is positive, and the sign of the sine matches that of the tangent.

This more complicated computation gives the same result as above.

4 0
3 years ago
Find the value of X and Y.
Elis [28]

Answer:x=63.4° y= 8.16

Step-by-step explanation:

5 0
3 years ago
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