If two fractions have the same denominator, the fraction with the larger numerator is the larger number.
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for

the center is (h,k) and the radius is r
and the distance formula is
distance between

and

is

r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so



the radius is

center is (-2,3)
find distance between (8,4) and (-2,3)






≈4.2

≈10.04
do r<D
(8,4) is outside the circle
Answer:
352
Step-by-step explanation:
(216-128)*(4)
(88)*(4)
352
Answer:
I know for a fact that x is 4.3 so that means 4.2 is less than x and 4.4 is greater than x
here are the steps whether you like it or not
step:1 4.1^2+1.3^2=18.5
step:2 √18.5=4.3
P(3) = 1/6
P(odd) = 3/6 = 1/2 ........(odd = 1,3,5)
P(less than 5) = 4/6 = 2/3.....(less than 5: 1,2,3,4)
P(prime) = 3/6 = 1/2 ..........(prime: 2,3,5)
P(4 or 6) = 2/6 = 1/3
P(not 1) = 5/6 .....................(not 1: 2,3,4,5,6)
hope it helps