Label the given points as follows:
A (0, 5)
B (2, 2)
C (3, 1)
D (4, -1)
The straight line has a constant slope. Therefore it should have the same value when any two of the four points are used to calculate the slope.
Try A and B:
Slope = (2 - 5)/(2 - 0) = -3/2
Try A and C:
Slope = (1 - 5)/(3 - 0) = -4/3
Try A and D.
Slope = (-1 - 5)/(4 - 0) = -3/2
Try B and D.
Slope = (-1 - 2)/(4 - 2) = -3/2
Clearly, C does not lie on the straight line.
Answer: The point that the graph does not pass through is (3,1).
Answer:
B. x < -1
Step-by-step explanation:
Hello!
Let's put them in order from greatest to least:
Given our possible inequalities, we need to find the inequality that contains all of these values.
The inequality that works is x < -1, as <u>all values are less than -1.</u>
Therefore, the answer is B. x < -1.
- 3x + 2x + 5 + 5x + 15 = 180 [angles on a line add to 180 degrees]
- 10x + 20 = 180 [combine like terms]
- 10x = 160 [subtract 20 from both sides]
- x = 16 [divide both sides by 10]
Arc AB measures 3(16) = 48 degrees.
Arc BC measures 2(16) + 5 = 41 degrees.
Answer:
The answer is 1,550
Step-by-step explanation:
First you find the area of the rectangle 1
Area = ab
=(21 in) (17in)
=357 sq in.
this will be the same for rectangle 3 = 357 sq. in.
next find the area of rectangle 2
area=ac
=(21 in) (11 in)
=231 sq in.
this will be the same for rectangle 4 = 231 sq. in.
next find the area of rectangle 5
area = bc
=(17 in) (11 in.)
=187 sq. in
this will be the same for rectangle 6 = 187 sq. in.
Next add all areas together
Total surface area = 2(ac) + 2(ab) + 2(bc)
= 2(231) sq in. + 2(357) sq in. + 2(187) sq. in
= 462 + 174+ 374
= 1550 sq. in
