Answer:
I. First number, a = 40.
II. Second number, b = 50.
III. Third number, c = 120.
Step-by-step explanation:
Let the three numbers be a, b and c respectively.
Given the following data;
Translating the word problem into an algebraic equation, we have;
a + b + c = 210
b = a + 10
c = 3a
Substituting the value of b and c into the equation, we have;
a + a + 10 + 3a = 210
5a + 10 = 210
5a = 210 - 10
5a = 200
a = 200/5
<em>a = 40</em>
To find the value of b;
b = a + 10
b = 40 + 10
<em>b = 50</em>
To find c
c = 3a
c = 3*40
<em>c = 120</em>
Answer:
21
Step-by-step explanation:
- 7 for first 10 shots
- 7 for another 10 shots
- 7 for last 10 shots
Answer:
x=− 9
/4
or
=−2.250
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer:
26%
Step-by-step explanation:
345. 24 - 274 = 71.24
71.24 / 274 =0.26
0.26 * 100 = 26
