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polet [3.4K]
3 years ago
14

Grayson is designing a rectangular athletic field. On a scale drawing the vertex of the rectangle are (4, 5), (9, 10) ,and (9, 5

). What are the coordinates of the fourth vertex?
A. (4, 9)
B. (4, 10)
C. (5, 10)
D. (5, 9)
Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

b

Step-by-step explanation:

alexgriva [62]3 years ago
5 0

The answer is b) 4,10

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Read 2 more answers
Worth 30 points. i really need help.
omeli [17]

Answer: a) w = -26, -2

b) x = -4,  -1

c) k = 17, -1

d) z = 65, 935

Multiple choice: D)

Step-by-step explanation:

a) (w+26)(w+2) = 0

w = -26, w = -2

b) (x+4)(x+1) = 0

x = -4, x = -1

c) (k-17)(k+1) = 0

k = 17, k = -1

d) (z-65)(z-935) = 0

z = 65, x z 935

Multiple Choice

D)

Multiply all terms by 2.

<h2><u><em>PLEASE MARK AS BRAINLIEST!</em></u></h2>
5 0
3 years ago
A football is passed through the air and caught at ground level for a touchdown. The height of the ball (h) is given by h= -d² +
IgorC [24]

Answer:

d = 6+sqrt(42)=12.4807407

Step-by-step explanation:

h= -d² + 12d + 6

The ball is caught at ground level  which means h=0

0 =  -d² + 12d + 6

Subtract 6 from each side

-6 = -d^2 +12d

Factor out a - sign

-6 =-(d^2-12d)

Divide by -1

6 = d^2 -12 d

Complete the square

-12/2 = -6  then square it = 36

Add 36 to each side

6+36 = d^2 -12d +36

42 = (d-6)^2

Take the square root of each side

±sqrt(42) = sqrt( (d-6)^2)

±sqrt(42) =  (d-6)

Add 6 to each side

6±sqrt(42) =  (d-6)+6

6±sqrt(42) =  d

d = 6+sqrt(42)=12.4807407

d =6- sqrt(42)=-.480740698

Since the distance cannot be negative

3 0
3 years ago
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