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polet [3.4K]
3 years ago
14

Grayson is designing a rectangular athletic field. On a scale drawing the vertex of the rectangle are (4, 5), (9, 10) ,and (9, 5

). What are the coordinates of the fourth vertex?
A. (4, 9)
B. (4, 10)
C. (5, 10)
D. (5, 9)
Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

b

Step-by-step explanation:

alexgriva [62]3 years ago
5 0

The answer is b) 4,10

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How do i graph 2.5x+8y=200
julia-pushkina [17]

Answer:


Step-by-step explanation:

2.5x+8y=200

We want to get this in slope intercept form so we will solve for y

Subtract 2.5x from each side

2.5x-2.5x+8y=-2.5x +200

8y = -2.5x +200

Now divide by 8 on both sides

8y/8 = -2.5x/8 + 200/8

y = -.3125x +25

The y intercept is 25, so plot a point there

-.3125 = -5/16

Go down 5 and to the right 16 and plot a point.  Connect the two points to make a line.

6 0
3 years ago
?anybody know this need help prontoe
scoundrel [369]

Answer:

<P = 27°

Step-by-step explanation:

In a triangle, the sum of all three interior angles = 180

So triangle NOP, <N + <O + <P = 180

Plug in

9x - 1 + 3x - 2 + 2x + 1 = 180

14x = 2 = 180

14x = 182

x = 13

<P = 2x + 1

<P = 2(13) + 1

<P = 26 + 1

<P = 27

Answer:

<P = 27°

3 0
4 years ago
Read 2 more answers
The length of a rectangle is 2 meters more than its width. The area of the rectangle is 80 square meters. What is the length and
insens350 [35]

Answer:

Step-by-step explanation:

Formula

A = L * W

Givens

W = W

L = W + 2

Solution

Area = L*W

Area = (W+2)*W = 80            Remove the brackets.

Area = W^2 + 2W = 80         Subtract 80 from both sides.

Area = w^2+2W-80=80-80  Combine

Area = w^2 +2W-80 = 0        Factor.

Area = (w+10)(w - 8) = 0

W + 10 = 0 won't work

W = - 10 which isn't possible

W- 8 = 0

W = 8

L = 8 + 2 = 10

The answer looks like A

8 0
3 years ago
A buoy starts at a height of 0 in relation to sea level and then goes up. Its maximum displacement in either direction is 6 feet
svet-max [94.6K]

Answer:

h=6*sin(\frac{2\pi }{8}t)

Step-by-step explanation:

Since the buoy is going up and down, its motion is oscillatory, and therefore, it can be described by a trigonometric function.

The buoy starts at height of 0 in relation to the sea level, which means at time t=0, h=0, this tells us that trigonometric function modeling the buoy must be the sine function since for

h=A*sin(wt), at   t=0, h=0.

The maximum displacement of the buoy in either direction is 6 feet, this means we have

h=6*sin(wt)

now we need to figure out w.

The time it takes the buoy to get from its lowest point to its highest point is 4 seconds, that means the period T of oscillation is 2*4=8 seconds. The buoy returns to to the same place after one period, this means if the buoy started from 0, it will return to 0 after 8 seconds; therefore, from h=6*sin(wt) the we have:

wT=2\pi

w(8)=2\pi \\\\\boxed{w=\frac{2\pi }{8} }

Now the final equation looks like

h=6*sin(\frac{2\pi }{8}t)

8 0
3 years ago
Read 2 more answers
cody is reading a 520-page book this summer. he read 1\5 of the pages on sunday. he read 1\2 of the pages on tuesday. he read th
kirill115 [55]
Assume that on Tuesday he read 1/2 pages out of 520 pages not what's left of the book minus 1/5 of the pages that he read on Sunday.
Cody read 260 pages on Saturday.
4 0
4 years ago
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