All categories

3 years ago

If f(x)=1/2x+2, find f^-1(20)

Mathematics

1 answer:

Sedaia [141]3 years ago

4 0

Answer:

Nothing at allllllll

Step-by-step explanation:haha

You might be interested in

Malcolm had a 20% discount coupon for camping equipment. He bought a camp stove for $39.96. What was the original price of the c

Fudgin [204]

Answer: $ 50 after rounding to nearest cent

Step-by-step explanation:

%age price

80 $39.96

100 x

using cross product rule

x=39.96*100/80= $49.95

8 0

3 years ago

What is the GCF of 14 and 21

n200080 [17]

Hey there the answer is,

The Greates Common Factor (GCF) is: 7


Hope I helped!!!<3

8 0

3 years ago

Each bus for Philips Elementary School transports 40 students to school. There are 12 buses that transport students to school ea

8090 [49]

Answer:

480 students are transported to school each day.

Step-by-step explanation:

Since there are 12 buses and each one of them transports 40 students that means that the total amount of students will be equal to...

12 x 40 = 480

7 0

3 years ago

The sides of a triangle are x, x+7, and 2x-8. If the perimeter of the triangle is 47, what is x

kirza4 [7]

just like the previous one, we sum the sides to get the perimeter.

$\bf (x)+(x+7)+(2x-8)=47\implies 4x-1=47\implies 4x=48\\\\\\x=\cfrac{48}{4}\implies x=12$

8 0

2 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago