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1 year ago

Jaun's age, x, is 4 times his age 15 years ago

1 answer:

7 0

The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

<h3>How to rewrite the statement as an expression?</h3>

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

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hoa [83]

y = 1/3x +b

1 = 1/3(9) +b

1 = 3 +b

subtract 3 from both sides

-2 = b

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3 years ago

What's the lateral area of a right circular cone if the diameter of the base is 4 m and the slant height of the cone is 15m? Rou

Mekhanik [1.2K]

The formula for the lateral surface area of a right circular cone is:
$\pi rl$
where r is the radius of the base, and l is the slant height.
Plugging in the values we get:
$Lateral\ area= \pi \times \frac{4}{2} \times15\ m^{2}$

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4 years ago

What is the best result for h?

Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation $S=2\pi rh+2\pi r^2$ , you need to:

Apply the Subtraction property of equality and subtract $2\pi r^2$ to both sides of the equation.

Then you need to apply the Division property of equality and divide both sides of the equation by $2\pi r$ .

Then:

$S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h$

6 0

3 years ago

Read 2 more answers

A New dog leash with an attached flashlight was on dale for 20% off. if the original price was $16.50, what is the discounted pr

Kisachek [45]

20 divided 100 = .2 then u multiply 16.5 by .2 =3.3 then u subtract that from 16.5 and u get 13.2

3 0

3 years ago

A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While

Murljashka [212]

Answer:

The expected number of appearance defects in a new car = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = $\nu$ = $= \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61$ = 0.64

$\sigma^{2}$ = variation of E(X) = $\sum (X - \nu) ^{2}P(X)$ = $(3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61$

= $(2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61$ = 0.8704

standard deviation = $\sqrt{\sigma^{2}}$ = $\sqrt{0.8704^{2}}$ = 0.93(approximately)

4 0

3 years ago