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MissTica
3 years ago
6

Pls translate the verbal phrase into an algebraic expression

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0
Okay. So we are talking of twice the sum of 13 and x, which signals the distributive property. The sum means add. It is not greater than 15, so it can be less than or equal to, but not greater. Based off the problem, the expression would be 2(13 + x) ≤ 15.
Svetllana [295]3 years ago
7 0
2(13+x) < or equate to 15
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A trader made a profit of 24% by selling an article for 3,720cedis how much should he have sold it to make a profit of 48%​
arsen [322]
The answer is 7440
24%=3720
48%= 3720*2
48% = 7440
6 0
3 years ago
Find three consecutive integers whose sum is 57????
Setler79 [48]

Answer:18 19 20

Step-by-step explanation:"Consecutive"  means that the integers will follow each other in value, for example:  1, 2, 3 or 4, 5, 6.  Also, no decimals are needed here because "integers" are whole, counting numbers. Here is the set up:   Let x= the first integer     Then    X+1= 2nd consecutive integer   and x+2= 3rd  .  

Suppose that x=1   x+1= 1+1=2   and x+2=1+2=3   However, you need specific consecutive numbers whose sum is 57.  Remember that sum means to add:

x+  (x+1)  + (x+2) = 57                 Addition of all 3 consecutive numbers   Now solve for x

                                                   and substitute into each part to come up with the three integers:

3x + 3= 57        3x=54               x=54/3  =  18            x=18,   x+1= 18+1=19      x+2=18+2=20

Check your answer:  18+19+20=57                 57=57  Check

7 0
3 years ago
A shipping container contains seven complex electronic systems. Unknown to the purchaser, two are defective. Two of the seven ar
kodGreya [7K]

Answer:

     \large\boxed{\large\boxed{10/21}}

Explanation:

There are only two mutually exclusive possibilities for each complex electronic system: being <em>defective</em> or being <em>not defective</em>:

  • Number of complex electronic systems: 7
  • Nmber of defective systems: 2
  • Number of not defective systems: 5

<em>Probability </em>that no defective systems are found in the sample is the equal to the probability of selecting them consecutively without replacement and finding each one is not defective:

  • Porbability the first is not defective × probability the second is not defective

  • 5/7 × 4/6 = 20/42 = 10/21

4 0
3 years ago
14. Find the value of the function:<br> If f(x) = 4x + 4x - 4, find f(0).<br> f(0) =
n200080 [17]

Answer:

<h2>f(0) = -4</h2>

Step-by-step explanation:

f(x)=4x^2+4x-4\ or\ f^*(x)=4x+4x-4=8x-4\\\\f(0)-\text{put}\ x=0\ \text{to}\ f(x):\\\\f(0)=4(0)^2+4(0)-4=4(0)+0-4=0-4=-4\\\\f^*(0)=8(0)-4=0-4=-4

3 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

#SPJ4

6 0
1 year ago
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