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MissTica
3 years ago
6

Pls translate the verbal phrase into an algebraic expression

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0
Okay. So we are talking of twice the sum of 13 and x, which signals the distributive property. The sum means add. It is not greater than 15, so it can be less than or equal to, but not greater. Based off the problem, the expression would be 2(13 + x) ≤ 15.
Svetllana [295]3 years ago
7 0
2(13+x) < or equate to 15
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In a box there are two prizes that are worth $4, a single prize worth $20, and a single prize worth $200. A player will reach in
Ronch [10]

Answer:

57

Step-by-step explanation:

The player has a 1/4 chance of drawing any of the 4 prizes. This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $20 is 1/4 and the probability of drawing a prize of $200 is also 1/4. To find the fair price of the game, we have to calculate the expected value that the player will gain. This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all the obtained values togueter. Thus, the fair price of the game is

4 * \frac{1}{2} + 20 * \frac{1}{4} + 200 * \frac{1}{4} = 57

6 0
3 years ago
GEOMETRY Help !! Which term describes the red curve in the figure below?
AleksandrR [38]
It is an elipse 
D is the answer
7 0
3 years ago
PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

8 0
2 years ago
In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=29°, and SQ = 5 feet. Find the length of QR to the nearest tenth of a foot.
goldfiish [28.3K]

Answer:

2.8 feet

Step-by-step explanation:

tan(29)=x/5

5tan(29)=x

2.8=x

8 0
3 years ago
Read 2 more answers
Which values represent solutions to Cosine (StartFraction pi Over 4 EndFraction minus x) = StartFraction StartRoot 2 EndRoot Ove
ddd [48]

Answer:

End fraction right brace

Step-by-step explanation:

I really hope I helped GL <33!

6 0
3 years ago
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