What is 4z - 3/z + 6 when z = −3? I need this asap!!
2 answers:
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Answer:
x - y + 6 = 0
Step-by-step explanation:
In normal form of a straight line, the equation is given by
where p is the perpendicular distance of the line from the origin and is the angle between the perpendicular line and the positive direction of the x-axis.
Here, in our case and
Degree,
Therefore, the normal form of the straight line equation is
⇒
⇒ {Since, Cos (180 - Ф) = - Cos Ф and Sin (180 - Ф) = Sin Ф}
⇒
⇒ - x + y = 3√2 × √2 = 6
⇒ x - y + 6 = 0
So, the standard form of the equation is x - y + 6 = 0. (Answer)