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vlabodo [156]
2 years ago
8

Will mark brainliest for full answer

Mathematics
1 answer:
Svet_ta [14]2 years ago
5 0

Answer:

y=2

Step-by-step explanation:

Hope it helps

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2 years ago
Each of three bags A, B, C contains white balls and black balls. A has a1 white &amp; b1 black, B has a2 white &amp; b2 black an
Alex73 [517]

Answer:

See explanation ( Answers are too long)

Step-by-step explanation:

We will first compute a general probability for picking a white ball:

          P (W) = a_1 / (a_1 + b_1) + a_2 / (a_2 + b_2) + a_3 / (a_3 + b_3)

part a)

We are asked to find the probability of white ball given that it pulled from bag A. So if we express it in notation we are asked for P ( A / W). We will use conditional probability to answer our question:

                           P ( A / W ) = P ( W & A ) / P (W)

                           P ( W & A ) = a_1 / (a_1 + b_1)

Hence,

P ( A / W ) = [a_1 / (a_1 + b_1)] / [a_1 / (a_1 + b_1) + a_2 / (a_2 + b_2) + a_3 / (a_3 + b_3)]    

part b)

We are asked to find the probability of white ball given that it pulled from bag B. So if we express it in notation we are asked for P ( B / W). We will use conditional probability to answer our question:

                           P ( B / W ) = P ( W & B ) / P (W)

                           P ( W & B ) = a_2 / (a_2 + b_2)

Hence,

P ( A / W ) = [a_2 / (a_2 + b_2)] / [a_1 / (a_1 + b_1) + a_2 / (a_2 + b_2) + a_3 / (a_3 + b_3)]    

part c)

We are asked to find the probability of white ball given that it pulled from bag C. So if we express it in notation we are asked for P ( C / W). We will use conditional probability to answer our question:

                           P ( C / W ) = P ( W & C ) / P (W)

                           P ( W & C ) = a_3 / (a_3 + b_3)

Hence,

P ( A / W ) = [a_3 / (a_3 + b_3)] / [a_1 / (a_1 + b_1) + a_2 / (a_2 + b_2) + a_3 / (a_3 + b_3)]    

     

6 0
3 years ago
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