Hi there!
To estimate, we can round:
591.3 is approximately 600
29 is approximately 30
Now, we divide:
600 / 30 = 20
Hope this helps!
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
X < -1
Step-by-step explanation:
4x - 5 + X < -10
5x < -5
× < -1
Answer:
There would be 120 different ways
Step-by-step explanation:
20×6=120
The degree is of this trinomial is 8
